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uysha [10]
2 years ago
8

Given a rectangle with lengths of 7 meters and widths of 5 metres,what would be the perimeter

Mathematics
1 answer:
Vsevolod [243]2 years ago
3 0

Answer:

Perimeter = 24 meters

step by step explanation

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The answer's are in the image sorry if you cant see them
Simora [160]
C. "David's equation is correct, because their spending will be multiplied by the number of months and then subtracted from their savings"

they are technically saying "Look we have 12,350 to use. How long (y) will the savings (12,350) last after using 240 each month (x)
so the amount they use *PER* month gets subtracted from the savings because they are using that money to pay with

Hope this helps :)
8 0
3 years ago
Graph a system of equations to solve log (−5.6x + 1.3) = −1 − x. Round to the nearest tenth.
Neporo4naja [7]

Answer:

Step-by-step explanation:

-2.1 and 0.2

8 0
3 years ago
Find and simplify the quotient 2/3 divided by 8/9
Anuta_ua [19.1K]
The answer is 3/4 and it was already simplified
8 0
3 years ago
Which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula?
AlexFokin [52]

An expression which shows the correct substitution of the values a, b, and c from the equation 0 = – 3x2 – 2x + 6 into the quadratic formula is: expression A. Therefore, the correct answer option is A.

<h3>What is a quadratic equation?</h3>

A quadratic equation can be defined as a mathematical expression (equation) that can be used to define and represent the relationship that exists between two or more variable on a graph. In Mathematics, the standard form of a quadratic equation is given by;

ax² + bx + c = 0

Mathematically, the quadratic formula is modeled or represented by this mathematical expression:

x = \frac{-b\; \pm \;\sqrt{b^2 - 4ac}}{2a}

From the information provided, we have the following values;

0 = -3x² - 2x + 6

Where:

a = -3

b = -2

c = 6

Substituting the values into the quadratic formula, we have;

x = \frac{-(-2)\; \pm \;\sqrt{(-2)^2 - 4(-3)(6)}}{2(-3)}\\\\x = \frac{2\; \pm \;\sqrt{4^2 - 4(-3)(6)}}{2(-3)}

Read more on quadratic equation here: brainly.com/question/4053652

#SPJ1

4 0
1 year ago
Solve 2cos x+2cos 2x=0 on the interval [0,2pi)
rjkz [21]
2cosx+2cos2x=0 \\ -2sin^2x+2cos^2x+2cosx=0 \\ -2(1-cos^2x)+2cos^2x+2cosx=0 \\ -2+2cos^2x+2cos^2x+2cosx=0 \\ 4cos^2x+2cosx-2=0 \\ t=cos x \\ 4t^2+2t-2=0 \\ \Delta=4+32=36 \\ t_1= \frac{-2-6}{8}=-1 \\ t_2= \frac{-2+6}{8}= \frac{1}{2}  \\ cos x=-1 \lor cos x= \frac{1}{2}    \\ x=-\pi \lor x= \frac{5\pi}{3}
6 0
3 years ago
Read 2 more answers
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