There is no solution ,<span>a+c=-10;b-c=15;a-2b+c=-5 </span>No solution System of Linear Equations entered : [1] 2a+c=-10
[2] b-c=15
[3] a-2b+c=-5
Equations Simplified or Rearranged :<span><span> [1] 2a + c = -10
</span><span> [2] - c + b = 15
</span><span> [3] a + c - 2b = -5
</span></span>Solve by Substitution :
// Solve equation [3] for the variable c
<span> [3] c = -a + 2b - 5
</span>
// Plug this in for variable c in equation [1]
<span><span> [1] 2a + (-a +2?-5) = -10
</span><span> [1] a = -5
</span></span>
// Plug this in for variable c in equation [2]
<span><span> [2] - (-? +2b-5) + b = 15
</span><span> [2] - b = 10
</span></span>
// Solve equation [2] for the variable ?
<span> [2] ? = b + 10
</span>
// Plug this in for variable ? in equation [1]
<span><span> [1] (? +10) = -5
</span><span> [1] 0 = -15 => NO solution
</span></span><span>No solution</span>
Answer:
9
Step-by-step explanation:
Write the fractions in fraction form 12/1 x 3/4
Multiply numerator x numerator and denominatior x denominato
You will get 36/4
36/4 = 9
I'm going to assume that you are asking how a number can have two factors.
So, a factor is an integer (non-fractional/decimal number) you multiply by another integer to get the actual number.
Well, let's look at the number 4. The number four has the following factors:
1, 2, 4
In a 'rainbow' style, you match the two outer numbers, then the two next inner numbers, and so on.
Because the number '2' is the one in the center and there is no other number to multiply it by, it must multiply by itself to reach the number 4.
Well, you must have two numbers to actually multiply together, so every number has two factors: 1, and itself (except for 0).
I hope this helps, and good luck :)
