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Lubov Fominskaja [6]
3 years ago
13

How can i get help with alegbra 2

Mathematics
2 answers:
disa [49]3 years ago
6 0
Watch videos on YouTube, that's what I do with geometry.
Wewaii [24]3 years ago
3 0
Ask your parents about getting you a personal tutor or ask you teach or show me what you need help with and i can help you
You might be interested in
HELP, thanks, If a triangle has a side length of 8 inches, and another side length of 5 inches, which of the
Anna71 [15]

Answer:

a. 7

Step-by-step explanation:

So a triangle a two sides that will always sum up to be greater than the third side.

Meaning:

a + b > c

a + c > b

b + c > a

So here, we're given a and b:

8 + 5 > c

8 + c > 5

5 + c > 8

Plug in the values:

13 > 7

15 > 5

12 > 8

These are all true, so it's probably 7.

13 > 2

10 > 5

7 > 8 This one is not true, so not 2.

13 > 13 This is not true, so not 13.

If not 13, we can't go any higher and so it can't be 15.

4 0
4 years ago
Simplify the equation
LekaFEV [45]

Answer:

you need to add an equation for us to simplify

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The ratio of 4 to 5. To 15
Oliga [24]
4:5 is to 12:15 because 4•3=12
7 0
3 years ago
Find the general solution, y(t), which solves the problem below, by the method of integrating factors.
Sonbull [250]

The general solution, y(t), which solves the problem by the method of integrating factors is; y = ¹/₂₁t⁴ + (1/t)c₁t^(⁴/₅)

<h3>How to solve differential equations?</h3>

We want to find the general solution of;

5t(dy/dt) + y = t⁴

We will divide through by 5t to get;

(dy/dt) + y/5t = t³/6

Using Integration factor, we have;

u(t) = e^∫(¹/₅t) dt = t^(¹/₅)

Thus, we now have;

[t^(¹/₅)](dy/dt) +  [t^(¹/₅)]y/5t = [t^(¹/₅)]t³/6

Completing this with a differential calculator gives us the general solution as;

y = ¹/₂₁t⁴ + (1/t)c₁t^(⁴/₅)

Read more about differential equations at; brainly.com/question/17201048

#SPJ1

7 0
3 years ago
How many pairs of whole numbers that have a sum of 12
Ymorist [56]
<span>Total numbers of whole number that has a sum of 12. Let’s start counting
1. 11 + 1 = 12
2. 10 + 2 = 12
3. 9 + 3 = 12
4. 8 + 4 = 12
5. 7 + 5 = 12
6. 6 + 6 = 12
7. 12 + 0= 12

Therefore, there are 7 pairs of whole numbers being added that have a sum of 12.

</span>



6 0
3 years ago
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