Hi there!
The term "difference" os the result of subtracting one number from another.
So in other terms you want to know what would be the result of subtracting -4.6 from 13.5 :
13.5 - -4.6 = Difference between the two temperatures
Two minus signs turn into a positive sign so :
13.5 - -4.6 =
13.5 + 4.6 =
18.1 = Difference between the two temperatures
Your answer is : The difference between the two temperatures is 18.1
There you go! I really hope this helped, if there's anything just let me know! :)
Answer: The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Step-by-step explanation: this is the same paragraph The square root of π has attracted attention for almost as long as π itself. When you’re an ancient Greek mathematician studying circles and squares and playing with straightedges and compasses, it’s natural to try to find a circle and a square that have the same area. If you start with the circle and try to find the square, that’s called squaring the circle. If your circle has radius r=1, then its area is πr2 = π, so a square with side-length s has the same area as your circle if s2 = π, that is, if s = sqrt(π). It’s well-known that squaring the circle is impossible in the sense that, if you use the classic Greek tools in the classic Greek manner, you can’t construct a square whose side-length is sqrt(π) (even though you can approximate it as closely as you like); see David Richeson’s new book listed in the References for lots more details about this. But what’s less well-known is that there are (at least!) two other places in mathematics where the square root of π crops up: an infinite product that on its surface makes no sense, and a calculus problem that you can use a surface to solve.
Answer:
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Answer: 262
Step-by-step explanation:
Get down the important info first:
m=7
n=17
Now replace the variables with the numbers. Your equation should be 17+35(7). First do the multiplication, 35x7, this will give you the answer 245. Now you add 17 to 245. You final answer should be 262.
First I would convert 20 and 12 to millimeters which would be 20= 200mm 12= 120mm. You would then find the area if the grid which would be 200•120=
