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lana [24]
2 years ago
13

If the length of a rectangle is 3 meters less than twice its width, what is an equation to find the length of the rectangle?

Mathematics
1 answer:
Liula [17]2 years ago
3 0

For this case we have to:

w: Represents the width of the rectangle

L: Represents the length of the rectangle

So, according to the statement we have:

The double width is represented as: 2w

3 meters less than twice the width is represented as:2w-3

Then we have that the length of the rectangle is given by the following equation:

L = 2w-3

Answer:

The length of the rectangle is given by:

L = 2w-3

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Please help me with this math problem. Only type answer please dont upload files
posledela
3) 3(8b + 3)
4) 57

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8 0
2 years ago
How do you do this? please help me
Anastaziya [24]

Answer:

f = 10, g = 4.8 cm

Step-by-step explanation:

Area of ABCE = 60 cm²

Area of ABCD = 48 cm²

So,

Area of ADE = 60-48

=> 12 cm²

Area of ADE = \frac{1}{2} (Base)(Height)

<u><em>Where Area = 12 cm², Base = 4 cm</em></u>

12 = \frac{1}{2}(4)(Height)

Height = 12-2

Height = 10 cm

Where Height is AD

So, AD = 10 cm

Also, <u><em>AD is parallel and equal to BC</em></u>(f)<u><em></em></u>

So,

f = 10 cm

<u><em>Now, Finding g</em></u>

Area of ABCD = Base * Height

<u><em>Where Area = 48 cm², Base = 10 cm</em></u>

48 = 10 * Height

Height = 48/10

Height = 4.8 cm

Whereas, Height is g

So, g = 4.8 cm

8 0
3 years ago
Ryan spent $26.32 on 8 gallons of gas. How much would he spend for 20 gallons?
nalin [4]
$65.80

$26.32/8=$3.29 for a gallon
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Hope this helps
4 0
3 years ago
Read 2 more answers
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tatiyna

Answer:

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Step-by-step explanation:

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3 0
3 years ago
In 3-4 sentences, describe how you would find a line parallel to the line 2x + 5y = 15 that goes through the point (-10, 1). Be
larisa86 [58]

the parallel line is 2x+5y+15=0.

Step-by-step explanation:

ok I hope it will work

soo,

Solution

given,

given parallel line 2x+5y=15

which goes through the point (-10,1)

now,

let 2x+5y=15 be equation no.1

then the line which is parallel to the equation 1st

2 x+5y+k = 0 let it be equation no.2

now the equation no.2 passes through the point (-10,1)

or, 2x+5y+k =0

or, 2*-10+5*1+k= 0

or, -20+5+k= 0

or, -15+k= 0

or, k= 15

putting the value of k in equation no.2 we get,

or, 2x+5y+k=0

or, 2x+5y+15=0

which is a required line.

6 0
1 year ago
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