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tresset_1 [31]
3 years ago
6

A square is inscribed in an isosceles right triangle with the length of the leg equal to 2 in. as shown on the figure. Find the

perimeter of the square.
pls help I need it asap!!!

Mathematics
1 answer:
exis [7]3 years ago
6 0

Answer:

4

Step-by-step explanation:

Since the triangle is isosceles, the side of the square is half the length of the side of the triangle, so is 1. The four sides of the square have a total length of 4.

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Step-by-step explanation:

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Follow the directions to solve the system of equations by elimination. 8x + 7y = 39 4x – 14y = –68 Multiply the first equation t
Hitman42 [59]

Answer:

The solution is ( 1/2 , 5)

Step-by-step explanation:

∵ 8x + 7y = 39 ⇒ (1)

∵ 4x - 14y = -68 ⇒ (2)

Multiply (1) by 2

16x + 14y = 78 ⇒ (3)

Add (2) and (3)

∴ 20x = 10 ⇒ x = 10 ÷ 20 = 1/2

∴ x = 1/2

By substitute in (1)

8(1/2) + 7y = 39 ⇒ 7y = 39 - 4 = 35 ⇒ y = 35 ÷ 7 = 5

∴ y = 5

∴ The solution is ( 1/2 , 5)

To check:

8(1/2) + 7(5) = 4 + 35 = 39 = R.H.S

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8 0
4 years ago
Read 2 more answers
Evaluate <br> 3^-3*3^4*3*3^-5
miss Akunina [59]
To multiply exponents with like bases, simply add the exponents...

3^-3 × 3^4 × 3 × 3^-5 =

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8 0
3 years ago
6a + 5a = 11 <br> Just a little confused thats all
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Answer

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Step-by-step explanation:

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Step-by-step explanation:

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