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tresset_1 [31]
3 years ago
6

A square is inscribed in an isosceles right triangle with the length of the leg equal to 2 in. as shown on the figure. Find the

perimeter of the square.
pls help I need it asap!!!

Mathematics
1 answer:
exis [7]3 years ago
6 0

Answer:

4

Step-by-step explanation:

Since the triangle is isosceles, the side of the square is half the length of the side of the triangle, so is 1. The four sides of the square have a total length of 4.

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A parallelogram has a length of 15cm and a height of 7.5cm . Calculate it’s area (step by step)
poizon [28]

Answer:

Area of parallelogram is equal to 112.5cm^2

Step-by-step explanation:

It is given length pf parallelogram which is equal to base of parallelogram is b=15 cm

Height of parallelogram h = 7.5 cm

We have to find the area of the parallelogram.

Area of parallelogram is equal to multiplication of base and height.

Therefore area of parallelogram is,

A=bh, here b is base and h is height.

So A=15\times 7.5=112.5cm^2

Therefore area of parallelogram is equal to 112.5cm^2

3 0
3 years ago
1.5 x 0.3 =<br> i’m desperate pls answer-
Natali5045456 [20]

Answer:

45

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=solve%20%3A%20%20-%20%20%5C%5C%20%20%5C%5C%20%20%2810%20%7B%7D%5E%7B2%7D%20%20-%206%20%7B%7D%5
o-na [289]

\longrightarrow{\blue{64}} 

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

= (10 {}^{2} - 6 {}^{2} )

= [(10 \times 10) - (6 \times 6)]

= (10 0- 36)

= 64

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}

4 0
3 years ago
Read 2 more answers
a cube has a edge length of 6 inches you multiply the side lengths by 4. how many times greater is the volume of the new cube
True [87]
24??? What is the old cube measurements???? Or these the the new cube measurements??
8 0
3 years ago
The product of two positive numbers is 1024. what is the minimum value of their sum?
Mrac [35]
Let the two positive numbers are x , y and there sum is s
So,
            x y = 1024 ⇒⇒⇒⇒ (1)
And        S = x + y ⇒⇒⇒⇒ (2)
by substituting from (1) at (2) with the value of y = 1024/x

∴ s = x + \frac{1024}{x}

Differentiating both sides with respect to x to find the minimum value of the sum and equating to zero

∴  \frac{ds}{dx} = 1 -  \frac{1024}{ x^{2} } = 0

solve the last equation for x
∴ 1 -  \frac{1024}{ x^{2} } = 0
    1 =  \frac{1024}{ x^{2} }  ⇒⇒⇒ *x²
∴ x²  = 1024
∴ x = \pm  \sqrt{1024} = \pm 32
taking the positive number as stated in the problem

x = 32

So, The numbers are 32 , 32
And theire mimimum sum = 32 + 32 = 64

  


8 0
3 years ago
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