Answer:
y = (x-3) ^2 +7
Vertex (3,7) minimum
Step-by-step explanation:
y=x^2-6x+16
The equation of a parabola in vertex form is
y = a(x - h)2 + k , where (h, k) is the vertex and a tells us where it opens up or down a>0 opens up and a < 0 opens down
First complete the square
Take the coefficient of the x term, divide by 2 and square it
-6 /2 = -3
(-3)^2 = 9
Take the 16 and split it into 9 and 7
y=x^2-6x+9 +7
y = (x-3) ^2 +7
The vertex is (3,7) and a=1
Since a =1, this opens up and if it opens up, the vertex is a minimum
