There are two so I'll give you the answer to both! 4,000 and 400
Answer:
Step-by-step explanation:
x decreases w/o bound, so x becomes a very large -ve no.
f(x)=5^(x-1) becomes 5^(large -ve no.) which will be almost zero
x increases w/o bound, so x becomes a very large +ve no.
f(x)=5^(x-1) becomes 5^(large +ve no.) which will keep increasing w/o bound
if u provide wat the choices are from ur Q in comments, i will pick the right one 4 u
Answer:
x =-3
Step-by-step explanation:
A hole of a simplified rarional funcrion as the one given above exists when there is a number that can make both the numerator & the denominator = 0
so plug -3 in the x of the function & you'll get 0/0 which is indeterminate & thus implies the existence of a hole
Answer:
12
Step by Step Explanation:
f(n+1) = 2f(n) + 10
a = 2, k = 10
a + k = 2 + 10 = 12
Answer: Choice A) y - 10 = 2(x - 3)
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Explanation:
We can rule out choices C and D because this diagonal line has a positive slope (as it moves uphill when moving to the right).
So m = 2 must be the slope.
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Recall that
y - y1 = m(x - x1)
represents the point slope form of a linear equation.
The point shown on this graph is (3,10) meaning that x1 = 3 and y1 = 10 pair up together.
So,
y - y1 = m(x - x1)
y - 10 = 2(x - 3)
which points to <u>choice A</u> as the final answer
