Answer:
The 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is between (0.104, 0.224).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is between (0.104, 0.224).
Answer:
3x^2
Step-by-step explanation:
Given:
(3x) * {(1/x)^-4 }* (x^-3)
=(3x) * {1 ÷ (1/x)^4} * {1/x^3}
=(3x) * {1(x/1)^4} * (1/x^3)
=(3x) * (x^4) * (1/x^3)
=(3x) (x^4) (1) / x^3
Multiply the denominators
=3x^5 / x^3
Can also be written as
=3*x*x*x*x*x / x*x*x
Divide the x
= 3*x*x / 1
=3x^2
The study has the smallest margin of error for a 98% confidence interval is <span>The northern California study with a margin of error of 3.2%.
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
</span>