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JulijaS [17]
3 years ago
6

How is a system of equations created when each linear function is given as a set of two ordered pairs? Explain

Mathematics
2 answers:
borishaifa [10]3 years ago
8 0

Answer:

If each linear function is given as a set of two ordered pairs, you need to use those points to find the equation of each line, and then solve the system of equations.

For example:

Let's say that f(x) has the following ordered pais: (a, b) and (c, d) and g(x) has the following ordered pais: (e, f) and (g, h). We know that the general equation of a line is the following:

(y - yo) = m(x-xo), where 'm' represents the slope and (xo, yo) any point from the line.

The slope will be given by: (y1 - yo)/(x1 - x0).

For example, the equation of the line of f(x) is:

f(x) = (y - b) = [(d - b)/(c - a)](x-a)

You do the same for the function g(x), and then you are all set to solve the system of equations!

Vanyuwa [196]3 years ago
8 0

Answer:

Sample response: Use the two points of a linear function to write an equation in slope-intercept form by first finding the slope of the function, and then using a point and the slope to determine the y-intercept. Write the equations in slope-intercept form.

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Answer:

\large\boxed{x=-2-\sqrt{\dfrac{11}{2}}\ \text{and}\ x=-2+\sqrt{\dfrac{11}{2}}}

Step-by-step explanation:

f(x)=2x^2+8x-3\\\\\text{You can use the quadratic formula:}\\\\ax^2+bx+c=0\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\text{We have}\ a=2,\ b=8,\ c=-3\\\\\text{Substitute:}\\\\b^2-4ac=8^2-4(2)(-3)=64+24=88\\\\\sqrt{b^2-4ac}=\sqrt{88}=\sqrt{4\cdot22}=\sqrt4\cdot\sqrt{22}=2\sqrt{22}\\\\x=\dfrac{-8\pm2\sqrt{22}}{2(2)}=\dfrac{-8}{4}\pm\dfrac{2\sqrt{22}}{4}=-2\pm\dfrac{\sqrt{22}}{2}=-2\pm\dfrac{\sqrt{22}}{\sqrt4}\\\\x=-2\pm\sqrt{\dfrac{22}{4}}=-2\pm\sqrt{\dfrac{11}{2}}

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