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Pavlova-9 [17]
3 years ago
11

A line passes through the points (1,2) and (4,4). What is the slope of the line

Mathematics
2 answers:
zubka84 [21]3 years ago
8 0

Answer:

Your answer is B-2/3

Step-by-step explanation:

ANEK [815]3 years ago
4 0

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (1, 2) and (4, 4).

Substitute:

m=\dfrac{4-2}{4-1}=\dfrac{2}{3}

Answer: B) 2/3

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3 years ago
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Solve for AE <br> what is the aswer
Pachacha [2.7K]
So triangles bcd and aec are similar. so this makes lines ac and bc similar and lines db and ae similar.

to solve this problem, we just need to do some algebra
\frac{ae}{ac} = \frac{bd}{bc}
now we substitute those values in
\frac{7x + 2}{9 + 3} = \frac{4}{3}
which results in
\frac{7x + 2}{12} = \frac{4}{3}
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5 0
3 years ago
In a certain year, the price of gasoline rose by 20% during January, fell by 20% during February, rose by 25% in March, and fell
satela [25.4K]

Using decimal multipliers, it is found that the value of x is of 16.67.

<h3>What is a decimal multiplier?</h3>

Increases of a% or decreases of a% re represented by decimal values, as follows:

  • The equivalent multiplier for an increase of a% is given by: \frac{100 + a}{100}
  • The equivalent multiplier for an decrease of a% is given by: \frac{100 - a}{100}

In this problem:

  • The price at the beginning of January was of a.
  • Increase of 20% in January, hence 1.2a.
  • Decrease of 20% in February, hence 1.2(0.8)a.
  • Increase of 25% in March, hence 1.2(0.8)(1.25)a.
  • Decrease of x% in April, hence 1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

The price of gasoline at the end of April was the same as it had been at the beginning of January, hence:

a =1.2(0.8)(1.25)\left(\frac{100 - x}{100}\right)a

1.2\left(\frac{100 - x}{100}\right) = 1

\left(\frac{100 - x}{100}\right) = \frac{1}{1.2}

\frac{100 - x}{100} = 0.8333

100 - x = 83.33

x = 16.67

The value of x is of 16.67.

To learn more about decimal multipliers, you can take a look at brainly.com/question/24952336

6 0
3 years ago
If the distribution of the population has a nonzero standard deviation and mean 10 then the probability that an individual data
RoseWind [281]

Answer:

FALSE

Step-by-step explanation:

The central limit theorem tell us that for a random sample of size n, the average of the sample will be approximately normally distributed with mean \mu and variance \sigma^2/n, where \mu and \sigma^2 are the mean a variance respectively of the sampling distribution. This always that the mean and the variance are both finite and the sample size n is greater than 30. We could use the central limit theorem, but in this case does not help us because we are considering 25 randomly selected data values, besides, we do not know the distribution of the original population.

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3 years ago
Can someone please help ASAP?!!!
Lostsunrise [7]

Answer:

Step-by-step explanation:

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