Equation of a line using 2 points. first find the slope
m= (y2-y1)/(x2-x1)= (3-3)/(-4-6)= 0/-10 = 0
m=0
using y-y1=m(x-x1)
we get
y-3=0(x-6)
y-3=0
y=3 is the equation of the line

- An isosceles triangle ABC
- AD is a bisector of ∠A
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- By ASA criteria ∆ABD congurant to ∆ADC
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- By CPCT ( corresponding parts of congurant triangle )

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Answer:
11 13/15
Step-by-step explanation:
-3 2/3+b = 8 1/5
Add 3 2/3 to each side
-3 2/3 + 3 2/3+b = 8 1/5+ 3 2/3
b = 8 1/5 + 3 2/3
We need to get a common denominator of 15
8 1/5 = 8 3/15
3 2/3 = 3 10/15
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11 13/15
We want to find

, for

.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:

.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)

.