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melisa1 [442]
4 years ago
10

You can buy 2 DVDs for the same price you would pay for 3 CDs selling for $13.20 a piece.Explain how you could find the price of

1 DVD.
Mathematics
1 answer:
egoroff_w [7]4 years ago
3 0
So,

3 CD's sell for $13.20 each.
3 * 13.20 = $39.60

$39.60 is also the price for 2 DVD's.

Divide $39.60 by 2.
$19.80

Each DVD is $19.80.
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Mice21 [21]
Equation of a line using 2 points. first find the slope

m= (y2-y1)/(x2-x1)= (3-3)/(-4-6)= 0/-10 = 0
m=0

using y-y1=m(x-x1)
we get
y-3=0(x-6)
y-3=0

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7 0
3 years ago
Pls help and no unnecessary typin* I will report
satela [25.4K]

\large\bf{\underline{Given :}}

  • An isosceles triangle ABC
  • AD is a bisector of ∠‎A

__________________________________________

\large\bf{\underline{To \:prove :}}

  • BD = DC

__________________________________________

\large\bf{\underline{In \: triangle \: ABD\:and\: triangle\:ADC}}

{⟹AD = AD\:\:\:\:\:\:\:\:\:\:\:\:\:\:( common)}

{⟹∠BAD = ∠CAD\:\:\:\:\:\:\:\:\:( given : AD \:is \:bisector \:of \:∠A )}

{⟹∠ABD = ∠ACD\:\:\:\:\:\:\:\:\:( given : angles\: in \:isosceles\: trianlge )}

\large\bf{\underline{Hence}}

  • By ASA criteria ∆ABD congurant to ∆ADC

__________________________________________

\large\bf{\underline{So}}

  • By CPCT ( corresponding parts of congurant triangle )

\large\bf{BD = DC}

__________________________________________

\large\bf{\underline{Note :}}Slide to view full answer.

6 0
3 years ago
Solve the equation <br> -3 2/3+b = 8 1/5<br><br> B= 5 3/5<br> B= 4 4/5<br> B= 11 3/5<br> B= 11 1/5
Readme [11.4K]

Answer:

 11 13/15

Step-by-step explanation:

-3 2/3+b = 8 1/5

Add 3 2/3 to each side

-3 2/3 + 3 2/3+b = 8 1/5+ 3 2/3

b = 8 1/5 + 3 2/3

We need to get a common denominator of 15

8 1/5 = 8 3/15

3 2/3 = 3 10/15

           ----------------

             11 13/15

4 0
3 years ago
What is dy/dx if y = (x2 + 2)3(x3 + 3)2? A. 3(x2 + 2)2(x3 + 3)2 + 2(x2 + 2)2(x3 + 3) B. 2x(x3 + 3)2 + 3x2(x2 + 2)3 C. 6x(x2 + 2)
Vlada [557]
We want to find \displaystyle{  \frac{dy}{dx}, for

            \displaystyle{ y=(x^2+2)^3(x^3+3)^2.

Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:

                                  (fg)'=f'g+g'f.

Thus,

 y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3

Answer: A)      3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3.



8 0
3 years ago
A box contains 6 red balls, 7 green balls and 5 blue balls. each ball is of different size. the probability that the red ball se
Strike441 [17]
6/18 good luck!!!!!!!!!!!!!!!!!!!
6 0
3 years ago
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