Answer:
I think its B but I have very little evidence. Don't even put B but I was just saying I think it is.
Step-by-step explanation:
Assume that each material in each category has an equal chance of being selected.
Categories:
(a) Type of wood used to make the cabinet: birch, maple, cherry.
Each type of wood has a probability of 1/3 to be selected.
(b) Type of finish: transparent, semi-transparent.
Each type of finish has a probability of 1/2 to be selected.
(c) Knob: bronze, steel, wood.
Each material has 1/3 probability to be selected.
Each event (selecting material for the cabinet, for the finish, and for the knob) is an independent event.
Therefore
Probablity(birch wood AND bronze knob) = (1/3)*(1/3) = 1/9
Probability(wood knob) = 1/3
Probability(transparent stain) = 1/2
Probability(cheryy wood AND semi-transparent stain) = (1/3)*(1/2) = 1/6
In ∆MKP and ∆MNP
MK = MN
PK = NP
MP = MP
SO ∆MKP AND ∆MNP ARE CONGRUENT.
SO m<PMN = m<PMK
m<NMK = 50
=> m<PMN + m<PMK = 50
=> 2 m<PMK = 50
=> m<PMK = 50/2 = 25°
