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3 years ago

Which number is a constant in the algebraic expression?

Mathematics

2 answers:

-BARSIC- [3]3 years ago

3 0

Answer:

sorry

Step-by-step explanation:

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klemol [59]3 years ago

3 0

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

-x^2 -6y+13x+7

The constant is the term with no variable attached to it

7 is the constant

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pishuonlain [190]

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3 years ago

Find the circumference of the circle P. Find the length of arc AB.

zaharov [31]

Answer:

A) 56.549

B) 9.425

Step-by-step explanation:

2(pi)r=56.54867

60/360x56.54867=9.425

6 0

3 years ago

Solve this: k/3 = -4

Veseljchak [2.6K]

Step-by-step explanation:

k/3= -4
k= -4×3
k= -12

<h2>stay safe healthy and happy.</h2>

6 0

3 years ago

Read 2 more answers

PLS HELP ME ASAP FOR 12 and 13!!! (SHOW WORK FOR BOTH!!!) + LOTS KF POINTS!!

pychu [463]

12.
Distribute the negative
2x - 5 - 9y + 8 + 16y
Simplify
2x + 7y + 3

13.
Square is 4 sides, all sides are equal
4 ( 4x + 3)
16x + 12

Please mark Brainliest if it helped.

8 0

3 years ago

Write (8a-^3) -2/3 in simplest form

Anna71 [15]

$(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Solution:

Given that,

$(8a^{-3})^{\frac{-2}{3}$

We have to write in simplest form

Use the following law of exponent

$(a^m)^n = a^{mn}$

Using this, simplify the given expression

$(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}$

Thus the given expression is simplified

8 0

3 years ago