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maks197457 [2]
3 years ago
14

Which number is a constant in the algebraic expression?

Mathematics
2 answers:
-BARSIC- [3]3 years ago
3 0

Answer:

sorry

Step-by-step explanation:

Djshxdhvhfiafhcbxzhadjfjc

klemol [59]3 years ago
3 0

Answer:

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

-x^2 -6y+13x+7

The constant is the term with no variable attached to it

7 is the constant

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Solve for x. Show your work. -12x < -12
Eva8 [605]

Step-by-step explanation:

-12x < -12

-12x/-12= x

-12/-12= 1

x < 1

3 0
3 years ago
Read 2 more answers
Solve for y and keep in simplest radical form
kumpel [21]
It’s c
You would use cah which is cosine
20 x cos(30
6 0
3 years ago
I need help, please!
Neporo4naja [7]

Answer:

2 of these numbers are divisible by 4 and 5.

20 and 60 are divisible by 4 and 5.

Step-by-step explanation:

20 is divisible by 4 and 5.

Divisible just means that the 4 (also the 5) goes into 20 evenly, with no remainder.

4 goes into 20 evenly with no remainder.

5 goes into 20 evenly with no remainder.

4 does not go into 35 evenly with no remainder.

35 ÷ 4 is 8 with a remainder of 3.

35 ÷ 4 = 8.75

5 does go into 35. 35 is divisible by 5.

35 is not divisible by 4.

60 is divisible by 4

60 ÷ 4 = 15 (no remainder, no extra decimals if you do it on a calculator)

60 ÷ 5 = 12 (no remainder, no extra decimals if you do it on a calculator)

60 is divisible by 4 and also by 5.

3 0
3 years ago
Graph a line that goes through (0, -2) and grows by 4
krok68 [10]
I’ve attached a sketch of what it would look like

4 0
3 years ago
Write the sum using summation notation, assuming the suggested pattern continues. -10 - 2 + 6 + 14 + ... + 110
Nimfa-mama [501]
This is the sum of the arithmetic sequence:
 10 - 2 + 6 + 14 + ... + 110
where:  a 1 = - 10, d = 8
a n = 110
a n = a 1 + ( n - 1 ) * d
110 = - 10 + ( n - 1 ) * 8
110 = - 10 + 8 n - 8
110 + 10 + 8 = 8 n
128 = 8 n
n = 128 : 8
n = 16
∑ n = n/2 * ( a 1 + a n ) 
∑ 16 = 16/2 * ( -10 + 110 ) = 8 * 100 = 800
Answer:
The sum is 800.
7 0
3 years ago
Read 2 more answers
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