Answer:
63n + 54
Step-by-step explanation:
9(6+7n)
First you have to multiply 6 and 9 which gives you 54. Then you’ll have to multiply 7n and 9 which equals to 63n. Whenever you see expressions like that, make sure to multiply both numbers inside the parentheses by what’s outside the parentheses. (Well, that method is mainly done like that if there’s one number outside the parentheses—like the expression you’ve provided.)
The correct answers are x≠2 and x≠(-2).
Domain restrictions are any points in the domain where the function will not have a value. This basically means that it's a point where x won't work in the function.
For the numerator, any value will work for x. We can have a value of 0 in the numerator, or a positive, negative, or decimal number.
However, the denominator cannot equal 0. This is because a fraction bar represents division, and we cannot divide by 0. The values that make the denominator 0 can be found by:
x²-4=0
Add 4 to both sides:
x²-4+4 = 0+4
x² = 4
Take the square root of both sides:
√x² = √4
x = 2 or x = -2.
Answer:
Step-by-step explanation:
I have no idea what formula that is you're using but the one I teach in both algebra 2 and in precalculus for continuous compounding is
where A(t) is the amount after the compounding, P is the initial investment, ee is Euler's number, r is the interest rate in decimal form, and t is the time in years. If our money doubles, we just have to come up with a number which will be P and then double it to get A(t). It doesn't matter what number we pick to double, the answer will come out the same regardless. I started with 2 and then doubled it to 4 and filled in the rest of the info given with time as my unknown:
Begin by dividing both sides by 2 to get
The only way we can get that t out of its current position is to take the natural log of both sides. Natural logs have a base of e, so
This is because they are inverses of one another. Taking the natural log of both sides:
Now divide by .062 to get
t = 11.2 years
2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
To solve for h
8h +16h equals 24 h
24h-12= 24h-12
these are equal so no !after what number you put in for h it will be a true statement. in situations like these my math teacher told me to put "all sol."
