Ask question

Ask question

All categories

3 years ago

14

A certain microscope is able to magnify an object up to 100,000 times its original size. In scientific notation, 100,000 is ____

_. 1 • 10-5 1 • 10-4 1 • 104 1 • 105

2 answers:

Aliun [14]3 years ago

7 0

The answer is 10^5. 10•10•10•10•10=100000

skad [1K]3 years ago

4 0

The answer i got is= is 10^5. 10•10•10•10•10=100000

You might be interested in

6 labour complete a work in 12 days. How many labours should added to complete the works in 8 days?

mario62 [17]

Answer:

9 labours

Step-by-step explanation:

In order to solve this, we must know which kind of proportionality is this. There are two types of proportions, direct and indirect/inverse proportions. In direct proportion, if one quantity increases, the other quantity also increases.

In indirect proportion, if one quantity increases, the other decreases and vice versa.

As per this question, we know if the number of labour increases, the number of days to complete a work decreases, thus proving that this is an indirect/inverse proportion.

6 labours => 12 days

x labours => 8 days

Since its an inverse proprotion, multiply 6 with 12, and x with 8.

8x = 6 × 12

x = $\frac{6*12}{8}$

∴ x = <u>9 labours</u>

7 0

2 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

5 0

3 years ago

Simplify each of the following powers of i. i^99=

Scorpion4ik [409]

I= sqrt (-1)

If the power is
- even then the value could be -1 or 1
-odd then the value could be -i or i

99 is odd so now is
-i if (99+1)/2 is even or is
i is (99+1)/2 is odd

Now check (99+1)/2= 100/2= 50,
50 is even so
i^99 = -i

8 0

3 years ago

Read 2 more answers

Please help ...........

viva [34]

I believe the answer is d

7 0

3 years ago

In an article about the cost of health care, Money magazine reported that a visit to a hospital emergency room for something as

ASHA 777 [7]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

Assume a normal distribution :

Mean (m) = 328

Standard deviation (sd) = 92

To obtain Zscore :

Zscore = (x - m) / sd

What is the probability that the cost will be more than $500?

x = $500

Zscore = (500 - 328) / 92 = 172 / 92 = 1.869 = 1.87

1 - p(Z < 1.87) = 1 - 0.9693 = 0.0307

b. What is the probability that the cost will be less than $250?

x = $250

Zscore = (250 - 328) / 92 = - 78 / 92 = - 0.8478 = - 0.85

p(Z < - 0.85) = 0.1977

c. What is the probability that the cost will be between $300 and $400?

x = 300

Zscore = (300 - 328) / 92 = - 28/ 92 = -0.30

p(Z < - 0.3) = 0.3821

x = 400

Zscore = (400 - 328) / 92 = 72/ 92 = 0.783

p(Z < 0.783) = 0.7823

0.7823 - 0.3821 = 0.4002

d. If the cost to a patient is in the lower 8% of charges for this medical service, what was the cost of this patient’s emergency room visit?

Probability is lower 8%

P (Z < Zscore) = 0.08

Zscore of 0.08 corresponds to - 1.41 on the z table

Zscore = (x - m) / sd

-1.41 = (x - 328) / 92

-129.72 = x - 328

-129.72 + 328 = x

x = 198.28

4 0

3 years ago