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Sati [7]
3 years ago
8

Multiply. −49×58 Enter your answer as a fraction, in simplified form,

Mathematics
2 answers:
brilliants [131]3 years ago
7 0
The answer would be -2842 hope i helped good luck :)
Nezavi [6.7K]3 years ago
7 0
The answer is -2,842
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In the polynomial below.
algol [13]

Answer:

Step-by-step explanation:uywegfywieflwef

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3 0
2 years ago
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If f(x)=-5x-11, then f^-1(x)=
Ludmilka [50]
F^-1(x) is the inverse so...
f^-1(x) = (-1/5)x - 11/5 

7 0
3 years ago
How do you write an exact angle measure without approximating to a decimal value?
dimulka [17.4K]

an exact angle measure without approximating to a decimal value is given below.

Step-by-step explanation:

Since an angle of 2 has degree measure 360° it follows that an angle of 1 radian has degree measure (180/ )°. Likewise, an angle of size 1° has radian measure /180. We now can easily obtain a formula to convert from degrees to radians and vice-versa. To convert from degrees to radians, multiply the angle by /180.

convert decimal degrees to DMS :

  • For the degrees use the whole number part of the decimal.
  • For the minutes multiply the remaining decimal by 60. Use the whole number part of the answer as minutes.
  • For the seconds multiply the new remaining decimal by 60.
4 0
3 years ago
The smaller triangle was dilated to form the larger triangle what is the value of x
Sladkaya [172]

Answer:

i think c which is 14

3 0
3 years ago
Evaluate the given integral by changing to polar coordinates. 8xy dA D , where D is the disk with center the origin and radius 9
BabaBlast [244]

Answer:

0

Step-by-step explanation:

∫∫8xydA

converting to polar coordinates, x = rcosθ and y = rsinθ and dA = rdrdθ.

So,

∫∫8xydA = ∫∫8(rcosθ)(rsinθ)rdrdθ = ∫∫8r²(cosθsinθ)rdrdθ = ∫∫8r³(cosθsinθ)drdθ

So we integrate r from 0 to 9 and θ from 0 to 2π.

∫∫8r³(cosθsinθ)drdθ = 8∫[∫r³dr](cosθsinθ)dθ

= 8∫[r⁴/4]₀⁹(cosθsinθ)dθ

= 8∫[9⁴/4 - 0⁴/4](cosθsinθ)dθ

= 8[6561/4]∫(cosθsinθ)dθ

= 13122∫(cosθsinθ)dθ

Since sin2θ = 2sinθcosθ, sinθcosθ = (sin2θ)/2

Substituting this we have

13122∫(cosθsinθ)dθ = 13122∫(1/2)(sin2θ)dθ

= 13122/2[-cos2θ]/2 from 0 to 2π

13122/2[-cos2θ]/2 = 13122/4[-cos2(2π) - cos2(0)]

= -13122/4[cos4π - cos(0)]

= -13122/4[1 - 1]

= -13122/4 × 0

= 0

5 0
3 years ago
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