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Strike441 [17]
3 years ago
12

Please help, im stuck. ​

Mathematics
1 answer:
Zina [86]3 years ago
5 0

Answer:

4x^2 + 12x + 9

Step-by-step explanation:

(2x + 3)^2

it is in the form of (a + b)^2

(a + b)^2 = a^2 + 2*a*b + b^2

(2x + 3)^2

(2x)^2 + 2*2x*3 + (3)^2

4x^2 + 12x + 9

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Write a function rule for the table. (b is incorrect so please choose one of the other 3 answers.)
pochemuha

Answer: D

Step-by-step explanation: payment equals to money earned per hour (p=6.25h).

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1, what is p(yellow, green) if there are 4 blue, 3 green, 2 yellow marbles
Mariulka [41]
1. \frac{2}{3}

2. \frac{4}{4} or 1

3. \frac{3}{9}

4. \frac{0}{0}
6 0
3 years ago
Judy Garland Electronics operate on a net-profile rate of 20% on its printer cables. If the markup is $8.95 and the overhead is
Ratling [72]

Answer:

The selling price is $79.53 .

Step-by-step explanation:

Formula

Profit\ percentage = \frac{Profit\times 100}{Cost\ price}

Let us assume that the cost price be x .

As given

Judy Garland Electronics operate on a net-profile rate of 20% on its printer cables.

If the markup is $8.95 and the overhead is $4.31 .

Selling price = Cost price + Markup price + Overhead price

Putting all the values in the above

                   = x + 8.95 + 4.31

                  = x + 13.26

Profit = Selling price - Cost price

         = x + 13.26 - x

         = 13.26

Putting all the values in the above

20 = \frac{13.26\times 100}{x}

x = \frac{13.26\times 100}{20}

x = \frac{1326\times 100}{20\times 100}

x = \frac{1326}{20}

x = $ 66.3

Thus

Selling price = x + 13.26

                    = 66.3 + 13.26

                    = $ 79.53

Therefore the selling price is $79.53 .

6 0
3 years ago
A coin, having probability p of landing heads, is continually flipped until at least one head and one tail have been flipped. (a
Natali [406]

Answer:

(a)

The probability that you stop at the fifth flip would be

                                   p^4 (1-p)  + (1-p)^4 p

(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

Step-by-step explanation:

(a)

Case 1

Imagine that you throw your coin and you get only heads, then you would stop when you get the first tail. So the probability that you stop at the fifth flip would be

p^4 (1-p)

Case 2

Imagine that you throw your coin and you get only tails, then you would stop when you get the first head. So the probability that you stop at the fifth flip would be

(1-p)^4p

Therefore the probability that you stop at the fifth flip would be

                                    p^4 (1-p)  + (1-p)^4 p

(b)

The expected numbers of flips needed would be

\sum\limits_{n=1}^{\infty} n p(1-p)^{n-1}  = 1/p

Therefore, suppose that  p = 0.5, then the expected number of flips needed would be 1/0.5  = 2.

7 0
3 years ago
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