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Oxana [17]
2 years ago
8

What is the midpoint of the segment shown below?

Mathematics
1 answer:
sashaice [31]2 years ago
3 0

Answer:

Step-by-step explanation:

average of x-coordinates = (-11+9)/2 = -1

average of y-coordinates = (0-1)/2 = -½

midpoint: (-1,-½)

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Step-by-step explanation:

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Find −1/5+17/10. Please help me!
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What is the solution to this inequality x-7&gt;8
Veronika [31]

Answer:

Choice a: x>5

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All you have to do on this one is add the 7 on both sides.

x-7>8\\x>5

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Story problems for division with fractions
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Mr. Smith has 5 2/4 lb. of dry fish food. He will put an equal amount of food into 4 containers. How much fish food will be in each container. 
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3 years ago
ank A contains 80 gallons of water in which 20 pounds of salt has been dissolved. Tank B contains30 gallons of water in which 5
adell [148]

Answer:

\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}

\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}

x(0)=20,y(0)=5

Step-by-step explanation:

We are given that

Tank A contains water=80 gallons

x(0)=20,y(0)=5

Tank B contains water=30 gallons

Rate=4 gallon/min

Concentration of salt  is pumped into tank=0.5 pound /gallon of water

Solution pumped from tank A to tank B at the rate=6 gallons/min

Solution pumped from tank B to tank A at the rate=2gallon/min

Solution from tank B is pumped out of the system at the rate=4 gallon/min

We have to find the DE at time t

For x

Rate in=0.5\times 4+y(t)/30\times 2

Rate in=2+y/15

Rate out=x/80\times 6

Rate out=3x/40[/tex]

\frac{dx}{dt}=Rate in-Rate out

\frac{dx}{dt}=2+y/15-3x/40

\frac{dx}{dt}=2-\frac{3}{40}x+\frac{y}{15}

For y

Rate in=x/80\times 6

Rate in=3/40x

Rate out=y/30\times (4+2)

Rate out=y/5

\frac{dy}{dt}=Rate in-Rate out

\frac{dy}{dt}=\frac{3}{40}x-\frac{y}{5}

8 0
2 years ago
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