D- (-2,3) :)
hope that helps
Y(initial) = 9
V(initial) = 168
V(final) = 0
g(accel-grav) = 32 (in feet per second
squared)
Use the following equation:
V(final) = V(initial) + a(t)
Since this object is moving straight up and
down, a = -32
Enter the knowns into the equation
0 = 168 - 32t
32t = 168
t = 168/9.8
t = 5.25
Now that you know the time it takes to
reach it's maximum, use the general
kinematics equation to solve for final
distance:
y(final) = y(initial) + V(initial)(t) + (1/2)a
(t²)
y(final) = 9 + 168(5.25) + (1/2)(-32)
(5.25²)
= 9 + 882 - 441
= 450 feet
Just little pieces. Normally round chips or squares but you can use anything
<span>12*(4x−5)/52=10 if this is the equation
the value for x would be
x </span>≈ 12
Answer:
The required inequality is
.
Jhon can buy at most 5 books.
Step-by-step explanation:
Consider the provided information.
Part(A)
Let b represent the number of books John buys.
He wants at least $10 in his savings account which means if we subtract the cost of books from $40 we have at least $10 left.

The required inequality is
.
Part(B)




Part(C): Jhon can buy at most 5 books.