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4 years ago

If the cube has a side length of 12 inches, what is the surface area of the cube?

1 answer:

8 0

The equation for surface area on a cube is 6 * L^2, where L is side length. Essentially, six squares of equal size
12^2=144
6 * 144=864
I hope you found this both helpful and explanatory

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A ferris wheel

Elena L [17]

Answer:

12375

Step-by-step explanation:

one rotation: 495

25 rotations x 495 seconds

12375 seconds

5 0

3 years ago

Read 2 more answers

3 = q/11 i need it real quick

makkiz [27]

Answer:

$q=33$

Step-by-step explanation:

So we have:

$3=\frac{q}{11}$

Multiply both sides by 11:

$11(3)=(11)\frac{q}{11}$

The right side cancels:

$11(3)=q$

Multiply the left:

$33=q$

Thus, the value of q is 33.

7 0

3 years ago

Read 2 more answers

Left parenthesis 5 plus 2 square root of 6 right parenthesis squared = a plus b square root of 6 then the value of a and b are

Ganezh [65]

Answer:

The values of $a$ and $b$ are $33$ and $\frac{20\sqrt{3}}{3}$ , respectively.

Step-by-step explanation:

The statement is equivalent to the following mathematic expression:

$\left(5 + 2\sqrt{2})^{2} = a + b\cdot \sqrt{6}$ (1)

By definition of the perfect square trinomial:

$25 + 20\cdot \sqrt{2} + 8 = a + b\cdot \sqrt{6}$

$33 + 20\sqrt{2} = a + b\cdot \sqrt{6}$

And by direct comparison we have the following system:

$a = 33$ (2)

$b\cdot \sqrt{6} = 20\sqrt{2}$ (3)

By (3), we solve for $b$ :

$b = \frac{20}{\sqrt{3}}$

$b = \frac{20\sqrt{3}}{3}$

The values of $a$ and $b$ are $33$ and $\frac{20\sqrt{3}}{3}$ , respectively.

6 0

3 years ago

winnie and kevin like to create their own triathlon courses to challenge each other. last weekend, winnie created a course that

shepuryov [24]

If you add all of the numerators together
3+57+13= 73
Then you would divide that number by 4
73/4= 18.25
So the course would be 18.25 or 18 1/4 miles long.

8 0

3 years ago

What is the slope of a line that is parallel to the line y = 3/4x + 2?

alexandr402 [8]

3/4
when it’s parallel it has the same slope!

5 0

3 years ago