What number must be multiplied on both sides in order to isolate x on the left side of this equation? 3/4x=1

IF YOU HELP ME ILL give U 2$ AFTER UR DONE

nordsb [41]

Answer:

LOL i dont need money jus mark me brainliest :P

Step-by-step explanation:

$distance = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

$AB = \sqrt{(6--2)^2 + (2-4)^2} = \sqrt{8^2 + 2^2} = \sqrt{68}\\\\BC = \sqrt{(1-6)^2 + (-1-2)^2} = \sqrt{5^2 + 3^2} = \sqrt{34}\\\\AC= \sqrt{(1--2)^2 + (-1-4)^2}} = \sqrt{3^2 + 5^2 } = \sqrt{34}$

$Clearly, this\ satisfies \ the\ Pythagoras\ theorem : AC^2 = AB^2 + BC^2$

$(\sqrt{68})^2 = (\sqrt{34} )^2 + (\sqrt{34} )^2\\\\68 = 34 + 34 \\68 = 68\\Hence\ satisfies .$

Therefore, the triangle ABC is a right angle triangle.

4 0

3 years ago

Current research indicates that the distribution of the life expectancies of a certain protozoan is normal with a mean of 49 day

zimovet [89]

Answer:

The probability that a simple random sample of 64 protozoa will have a mean life expectancy of 54 or more days is P(M>54)=0.00004.

Step-by-step explanation:

In this case, we have a population lifetime normally distributed with mean 49 and standard deviation 10.2.

We take a sample of size n=64.

Then, we can calculate the z-score for a sample mean M=54, in order to calculate P(M>54):

$z=\dfrac{X-\mu}{\sigma/\sqrt{n}}=\dfrac{54-49}{10.2/\sqrt{64}}=\dfrac{5}{1.275}=3.922\\\\\\P(M>54)=P(z>3.922)=0.00004$

The probability that a simple random sample of 64 protozoa will have a mean life expectancy of 54 or more days is P(M>54)=0.00004.

3 0

3 years ago

Y = x + 4

Alex777 [14]

X = -2
y = 2

You can get this by setting the two different y's equal to each other and solving for the x value.

3 0

3 years ago

Read 2 more answers

(1 point) A chain 64 meters long whose mass is 24 kilograms is hanging over the edge of a tall building and does not touch the g

miss Akunina [59]

Answer:

W = 2747,1 [J]

Step-by-step explanation:

Chain is 64 meters long with mass 24 Kg

Then weight of the chain is p = 24 * 9.8

p = 235.2 [N] N = kg*m/s²

And by meter is 235,2 / 64 = 3.675

Total work has two component

- work to lift the 13 top meters of chain W₁

W₁ = ∫₀ᵇ F(y) dy

- work to lift last ( 64 - 13 ) meters 51 W₂

W₂ = 3.675 * 51 * 13 Kg m² /s² [J]

W₂ = 2436,53 [J]

We need to calculate W₁

W₁ = ∫¹³₀ mgy dy ⇒ W₁ = ∫¹³₀ 3,675 ydy

W₁ = 3,675* ∫¹³₀ ydy W₁ = 3,675* y²/2 |₀¹³

W₁ = 3,675* 84,5 [J]

W₁ = 310,54 [J]

And total work W

W = W₁ + W₂

W = 310,54 + 2436,53 [J]

W = 2747,1 [J]

8 0

3 years ago

Can anyone here help me out?

Flauer [41]

Answer:

A)15x+30=weekly income

B)8 hours

Step-by-step explanation:

15x+30= weekly income

The 15 multiplies because it says per hour

The 30 is constant because she only earns it once (per week)

15x+30=150

minus 30 from both sides

15x=120

divide by 15

x=8

6 0

3 years ago