The amount invested in the first account is $9,300 while the amount invested in the second account is $8,800.
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How do we calculate the amount invested?</h3>
Let x represents the amount invested in the first account.
Therefore, we have:
Amount invested in the second account = x - 500
Interest income from first account = 3% * x = 0.03x
Interest income from second account = 5% * (x - 500) = 0.05x - 25
Total interest income = 0.03x + 0.05x - 25 = 719
Solving for x, we have:
0.08x = 719 + 25
x = 744 / 0.08
x = $9,300
Substituting for x, we have:
Amount invested in the second account = $9,300 - $500 = $8,800
Learn more about the amount invested here: brainly.com/question/24132106.
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Is there some question supposed to be attached?
X+29/6=9
(convert mixed fraction to improper)
x=9-29/6
x=25/6 (calculate the difference)
therefore your answer is x=25/6
or x=4 1/6 OR x= 4.16
