Answer:

Step-by-step explanation:
The diagram shows shaded region which boundary is bounded with two lines.
<u>Equation of the 1st line:</u>
This line passes through the points (-6,0) and (0,-6), so its equation is

<u>Equation of the 2nd line:</u>
This line passes through the points (-2,0) and (0,4), so its equation is

The origin belongs to the shaded region, so it must satisfy both inequalities, so
correct inequality is 
correct inequality is 
Note that signsare with notion "or equal to" because lines are solid.
Answer:

Answer:
Step-by-step explanation:
Answer:
2x (a+b)
Step-by-step explanation:
the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.
The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.
In terms of hyperbola, F1F2=2c, c=20.
The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.
Use formula c^2=a^2+b^2c
2
=a
2
+b
2
to find b:
\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}
(20)
2
=(18)
2
+b
2
,
b
2
=400−324=76
.
The branches of hyperbola go in y-direction, so the equation of hyperbola is
\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1
b
2
y
2
−
a
2
x
2
=1 .
Substitute a and b:
\dfrac{y^2}{76}- \dfrac{x^2}{324}=1
76
y
2
−
324
x
2
=1 .
I am lead to believe th =e answer would be 10,000 :)