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Kipish [7]
3 years ago
7

Two urns each contain green balls and blue balls. urn i contains 4 greenballs and 6 blue balls, and urn ii contains 6 green ball

s and 2 blueballs. a ball is drawn at random from each urn. what is the probabilitythat both balls are blue?
Mathematics
1 answer:
Lemur [1.5K]3 years ago
5 0
1st urn....4 green balls, 6 blue balls.....10 total balls....probability of drawing a blue ball in urn 1 is : 6/10 reduces to 3/5

2nd urn...6 green balls, 2 blue balls....8 total balls...probability of drawing a blue ball in urn 2 is : 2/8 reduces to 1/4

probability both balls are blue : 3/5 * 1/4 = 3/20 <==
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1) You deposit $2,500 in an account that earns 4% simple interest. How much do you earn in eight years?
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3 years ago
Solve the equation. 12x – 15 = 3(2x +3)
MA_775_DIABLO [31]

Answer:

x = 4

Step-by-step explanation:

Solve for x:

12 x - 15 = 3 (2 x + 3)

Hint: | Write the linear polynomial on the left hand side in standard form.

Expand out terms of the right hand side:

12 x - 15 = 6 x + 9

Hint: | Move terms with x to the left hand side.

Subtract 6 x from both sides:

(12 x - 6 x) - 15 = (6 x - 6 x) + 9

Hint: | Combine like terms in 12 x - 6 x.

12 x - 6 x = 6 x:

6 x - 15 = (6 x - 6 x) + 9

Hint: | Look for the difference of two identical terms.

6 x - 6 x = 0:

6 x - 15 = 9

Hint: | Isolate terms with x to the left hand side.

Add 15 to both sides:

6 x + (15 - 15) = 15 + 9

Hint: | Look for the difference of two identical terms.

15 - 15 = 0:

6 x = 9 + 15

Hint: | Evaluate 9 + 15.

9 + 15 = 24:

6 x = 24

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 6 x = 24 by 6:

(6 x)/6 = 24/6

Hint: | Any nonzero number divided by itself is one.

6/6 = 1:

x = 24/6

Hint: | Reduce 24/6 to lowest terms. Start by finding the GCD of 24 and 6.

The gcd of 24 and 6 is 6, so 24/6 = (6×4)/(6×1) = 6/6×4 = 4:

Answer:  x = 4

8 0
3 years ago
Given the below sequence:-1, -3, -5, -7, . . .
vekshin1

Answer:

A. The next 3 terms are —9, —11, —13

B. The sequence is Arithmetic

C. The sequence has a common difference of —2

Common difference = T2 — T1 or = T3 — T2

=T2 — T1 = —3 —(—1) = —2 or

= T3 — T2 = —5 —(—3) = —2

D. Tn = a + d(n—1)

a = first term = —1

d = Common difference = —2

n = 27

T27 = —1 + —2(27—1)

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3 0
3 years ago
PLZ HELP ME!!!
AnnZ [28]

Answer:

A: 6x^2(x^8-16)

B: 6x^2(x^4+4)(x^2+2)(x^2-2)

Step-by-step explanation:

<u>A:</u>

Our expression is 6x^{10}-96x^2. We need to find some common factors. Clearly, we can see that both terms share the x² part, so we can definitely take that out:

6x^{10}-96x^2

x^2(6x^8-96)

Let's see if 96 is divisible by 6:

96 ÷ 6 = 16; since there's no remainder / the remainder is 0, we know 96 is divisible by 6, so we can also factor out 6:

x^2(6x^8-96)

6x^2(x^8-16)

Thus, the answer to part A is 6x^2(x^8-16).

<u>B:</u>

Look at the x^8-16 part of the above factored expression. Notice that it is a difference of squares (because x^8=(x^4)^2 and 16 = 4²), so we can write this as:

x^8-16

(x^4+4)(x^4-4)

Now take a look at the (x^4-4) part. Again, it's a difference of squares because x^4=(x^2)^2 and 4 = 2², so rewrite that as:

x^4-4

(x^2+2)(x^2-2)

Put it all together:

6x^2(x^4+4)(x^2+2)(x^2-2)

Thus, the answer to part B is 6x^2(x^4+4)(x^2+2)(x^2-2).

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