two orienteering courses are a represented on suitable axes as 3x - 2y = - 17 and 3y - 4x =24 the courses have one checkpoint in
the common. Determinate, algebraically the coordinates of this checkpoint
1 answer:
3x - 2y = -17 -> 9x - 6y = -51
3y - 4x = 24 -> 6y - 8x = 48
9x - 6y = -51
6y - 8x = 48
------------------- +
x = -3
3x - 2y = -17
3(-3) - 2y = -17
-9 - 2y = -17
-2y = -8
y = 4
Coordinate : (-3, 4)
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