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miv72 [106K]
3 years ago
8

two orienteering courses are a represented on suitable axes as 3x - 2y = - 17 and 3y - 4x =24 the courses have one checkpoint in

the common. Determinate, algebraically the coordinates of this checkpoint​
Mathematics
1 answer:
Vitek1552 [10]3 years ago
6 0

3x - 2y = -17 -> 9x - 6y = -51

3y - 4x = 24 -> 6y - 8x = 48

9x - 6y = -51

6y - 8x = 48

------------------- +

x = -3

3x - 2y = -17

3(-3) - 2y = -17

-9 - 2y = -17

-2y = -8

y = 4

Coordinate : (-3, 4)

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There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


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-x^2(x^4 - 3x^2 - 4)

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Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

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