Please show work will give alot of points
1 answer:
1. F=ma
F = (2500)(4.8)
F = 12,000 N
2. a = F/m
a = 250/40
a = 6.25m/s^2
3. m = F/a
m = 50/1.2
m ≈ 41.67 kg
4. Speed = Distance covered/time
= 2300/4.25*
≈ 541.18 mph
*15 minutes is 0.25 hours (15 times 4 = 60)
5. same formula above
250/45 ≈ 5.56 km/min
remember these formula triangles for the future :)
F = (2500)(4.8)
F = 12,000 N
2. a = F/m
a = 250/40
a = 6.25m/s^2
3. m = F/a
m = 50/1.2
m ≈ 41.67 kg
4. Speed = Distance covered/time
= 2300/4.25*
≈ 541.18 mph
*15 minutes is 0.25 hours (15 times 4 = 60)
5. same formula above
250/45 ≈ 5.56 km/min
remember these formula triangles for the future :)
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Answer:
Step-by-step explanation:
You can observe in the figure that JK is a tangent and KH is a secant and both intersect at the point K. Then, according to the Intersecting secant-tangent Theorem:
You know that:
Then KE is:
Now you can substitute the value of KE and the value of KH into and solve for JK. Then the result is: