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Wewaii [24]
3 years ago
9

A company produces x units of a product per month, where c(x) represents the total cost and r(x) represents the total revenue fo

r the month. The functions are modeled by c(x)=300x+250 and r(x)=-0.5x^2+800x-100.
The profit is the difference between revenue and cost where p(x)=R(x)-C(x).
What is the total profit p(x), for the month?
Mathematics
1 answer:
Nat2105 [25]3 years ago
5 0

Answer:

The total profit P(x) or the month is P(x)=-0.5x^2+500x-350.

Step-by-step explanation:

A company produces x units of a product per month.

The total cost represents by the function C(x).

C(x)=300x+250

The total revenue represents by the function R(x).

R(x)=-0.5x^2+800x-100

The profit is the difference between revenue and cost.

P(x)=R(x)-C(x)

P(x)=-0.5x^2+800x-100-(300x+250)

P(x)=-0.5x^2+800x-100-300x-250

Combine like terms.

P(x)=-0.5x^2+(800x-300x)+(-100-250)

P(x)=-0.5x^2+500x-350

Therefore, the total profit P(x) or the month is P(x)=-0.5x^2+500x-350.

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