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Tom [10]
3 years ago
11

How many square inches are in 60 square feet?

Mathematics
2 answers:
antoniya [11.8K]3 years ago
6 0

Answer:

8640

Step-by-step explanation:

Delvig [45]3 years ago
4 0

Answer:

8640

Step-by-step explanation:

You might be interested in
E
AlexFokin [52]

For this case we have that by definition, the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It's the slope

(x_ {0}, y_ {0}): It is a point through which the line passes

According to the statement data we have:

m = 5\\(x_ {0}, y_ {0}): (- 8,1)

Substituting we have:

y-1 = 5 (x - (- 8))

By law of signs of multiplication we have to:

- * - = +\\y-1 = 5 (x + 8)

Answer:

The requested equation is: y-1 = 5 (x + 8)

5 0
3 years ago
Ishaan is 222 times as old as Christopher. 353535 years ago, Ishaan was 777 times as old as Christopher.
klemol [59]
<h3><u>Question:</u></h3>

Ishaan is 2 times as old as Christopher. 35 years ago, Ishaan was 7 times as old as Christopher. How old is Christoper now?

<h3><u>Answer:</u></h3>

The present age of Christoper is 42 years old

<h3><u>Solution:</u></h3>

Given that Ishaan is 2 times as old as Christoper

Let the present age of Christoper be "x"

Then, Present age of Ishaan = 2 times as old as Christoper

present age of Ishaan = 2x

<em><u>35 years ago, Ishaan was 7 times as old as Christopher</u></em>

Age of Ishaan 35 years ago = Present age of Ishaan - 35

Age of Ishaan 35 years ago = 2x - 35

Similarly,

Age of christoper 35 years ago = Present age of christoper - 35

Age of christoper 35 years ago = x - 35

From given statement, 35 years ago, Ishaan was 7 times as old as Christopher

Age of Ishaan 35 years ago = 7 times the age of Christoper 35 years ago

(2x - 35) = 7(x - 35)

<em><u>Solve the above equation for "x"</u></em>

2x - 35 = 7x - 245

2x - 7x = -245 + 35

-5x = -210

<h3>x = 42</h3>

Thus present age of Christoper is 42 years old

5 0
3 years ago
Need answer to 4 and 5
algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $ g_n  = 2 . 3^{n - 1} $

To find the first term, substitute n = 1.

Therefore, $ g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1  $ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3 $ = 6

$ g_3 =  2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9 $ = 18

$ g_4 = 2 . 3^{4  - 1} = 2 . 3^{3} = 2 . 27 $ = 54

$ g_5 =  2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81 $ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $ t_n = \frac{2}{3}t_{n - 1} $

$ t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1  = \frac{2}{3}6 $ = 4

$ t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3} $

$ t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9} $

$ t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27} $

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0
3 years ago
Task Directions: Ms. Chang's class decides to order posters that advertise a walkathon to raise money for
mamaluj [8]

Answer:

a.

Clear Prints = 2p

Sue = 15 + 0.5p

b.  10 posters

c.  See Below

d.  Clear Prints

e. See Below

Step-by-step explanation:

<u>Complete Question:</u>

<em>Ms. Chang’s class decides to order posters that advertise a walkathon to raise money for a local charity. Ichiro obtains quotes from two different companies.Clear Prints charges $2 per poster. Posters by Sue charges $15 plus $.50 per poster.</em>

<em>a. For each company, write an equation Ichiro could use to calculate the cost for any number of posters.</em>

<em>b. For what number of posters is the cost the same for both companies? Explain.</em>

<em>c. Which company do you think the class should buy posters from? Explain your reasoning.</em>

<em>d. If Ms. Chang’s class has an $18 budget for posters, which company do you think the class should buy posters from? </em>

<em>e. If Ms. Chang donates an additional $10 for ordering posters, does it impact the decision made? What factors influenced your decision?</em>

<em />

<u>Solution:</u>

a.

Let the number of posters be "p" so

Clear Print would take 2 * p or "2p"

Sue would take a fixed cost of $15 and 0.5p, so "15 + 0.5p"

b.

We want cost of both to be same. So we can equate:

2p=15 + 0.5p

Now, using algebra, we can solve for "p", the number at which both of the printers will cost same. Lets do this:

2p=15 + 0.5p\\2p-0.5p=15\\1.5p=15\\p=10

So, for 10 posters, the cost of both will be same

c.

It depends.

If the number of posters they order is LESS THAN 10, they should order from Clear Prints. If the number of posters they print is "10", then they can choose any one of the printers since cost would be same. If they print more than 10 posters, then they should choose to go with Sue, as it will cost less.

d.

If the budget is $18, they can get:

Clear Prints = 18/2 = 9 posters made

Sue = 15 already gone as fixed cost, so remaining is 18 - 15 = 3

At 0.5 per poster, 3/0.5 = 6 posters

So, taking Clear Prints would be better.

e.

The budget of 18 is increase by 10, so the budget is:

18 + 10 = $28

From clear prints, you can get:

28/2 = 14 posters

From Sue, you can get:

28 - 15(fixed cost) = 13 left for posters

13/0.5 = 26 posters

Definitely, Sue gives more, so decision made at $18 budget to get Clear Prints would be impacted because they should now go with Sue since it will give them better deal and more posters.

5 0
2 years ago
Volume of 29 mL and has a mass of 53 g what’s is the density
RSB [31]

Answer:  1.82

Step-by-step explanation:

Density = \frac{mass}{volume} *Divide the mass by volume.

= 1.82

8 0
3 years ago
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