I'll mark brainliest for the right answer! Please hurry!

What is AC?

Maru [420]

C. 6

Exploration: i got it right.

3 0

2 years ago

X^3+2/3x^4-1/2x^2 integral

Irina-Kira [14]

$\frac{2 {x}^{5} }{15} + \frac{ {x}^{4} }{4} - \frac{ {x}^{3} }{6} + c$

simplified form =

$\frac{ {x}^{3}(8 {x}^{2} + 15x - 10) }{60} + c$

5 0

3 years ago

A piece of rope 27m long is cut into two pieces so that one piece is four-fifths as long as the other. Find the length of each p

nata0808 [166]

Answer:

x+.8x=27

1.8x=27

x=15

4/5(15)=12

So 15 and 12

Step-by-step explanation:

8 0

3 years ago

At a local university, a sample of 49 evening students was selected in order to determine whether the average age of the evening

pav-90 [236]

Answer:

$z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4$

$p_v =2*P(z>4)=0.0000633$

When we compare the significance level $\alpha=0.1$ we see that $p_v$ so we can reject the null hypothesis at 10% of significance. So the the true mean is difference from 21 at this significance level.

Step-by-step explanation:

Data given and notation

$\bar X=23$ represent the sample mean

$\sigma=3.5$ represent the population standard deviation

$n=49$ sample size

$\mu_o =21$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:

Null hypothesis: $\mu = 21$

Alternative hypothesis: $\mu \neq 21$

The statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{23-21}{\frac{3.5}{\sqrt{49}}}=4$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(z>4)=0.0000633$

Conclusion

When we compare the significance level $\alpha=0.1$ we see that $p_v$ so we can reject the null hypothesis at 10% of significance. So the the true mean is difference from 21 at this significance level.

8 0

3 years ago

a fisherman catches 2 fish the amberjack weighs 3 times as much as the snapper,altogether the fish weigh 44 pounds how much does

Anna [14]

Because of the fact that the amberjack is essentially three snappers, it can be shown as 3s

since one snapper is one s, and the amberjack is 3s, we can combine like terms

s+3s = 4s

because altogether, the fish weigh 44 pounds, 4s would equal 44 (shown as 4s = 44), from there, simply divide by 4 on both sides to get the weight of a snapper;

s = 11

Small bonus (finding an amberjack)

Since an amberjack is equal to three snappers, and a snapper is 11 pounds, an amberjack would be 33 pounds.

8 0

3 years ago