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Marizza181 [45]
3 years ago
8

I'll mark brainliest for the right answer! Please hurry!

Mathematics
1 answer:
DaniilM [7]3 years ago
7 0

p=36

because 15 is 3 times 5 so just multiply the perimeter


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Wx+yz=bc , solve for z .
Aleksandr-060686 [28]
Wx+yz=bc
minus wx on both sides
yz=bc-wx
dividing 'y' on both sides
Hence,
z=(bc-wx)/y
Here is what you need.
Hope it helped
8 0
3 years ago
Read 2 more answers
Someone please help me with this! Is this a independent or dependent? Explain why.
irga5000 [103]

Answer:

  independent

Step-by-step explanation:

Dependent equations graph as the <em>same line</em>. These lines are not the same, so the equations are independent.

___

However, the lines are parallel, so the equations are also <em>inconsistent</em>. There is <em>no solution</em> to this system of equations.

6 0
3 years ago
Rewrite the following linear equation to slope form :y+2=7(2x-4)
garik1379 [7]

Answer:

y = 14x -30

Step-by-step explanation:

The slope intercept form is:

y = mx + b,

Slope intercept form is useful for finding the slope and y intercept of a line, hence why it is called "slope intercept" because it is easy to see the slope and the y intercept of a line in this form. Since the slope denoted by m, and y intercept denoted by b are clearly given.

y + 2 = 7(2x - 4)

Distribute 7 across the parentheses by multiplying x and 2x and 4 by 7.

y+2 = 14x - 28

subtract 2 from both sides. This cancels the 2 on the left and moves it to the right, while keeping the equation balanced.

y+2 -2 = 14x - 28 -2

y  = 14x - 30

y = 14x -30

As you can see our y = 14x -30 now looks like the point slope equation we had above. m = 14, and  b = -30. This means the line goes up 14 for every single unit you move to the right, and intersects the y axis at  (0, -30).

Please mark me brainliest.

4 0
4 years ago
What is the standard deviation of the data set? <br> 42,36,42,30,54,18
Oliga [24]

Answer:

the standard deviations 12.2 if I'm correct.

5 0
3 years ago
Read 2 more answers
The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=
Leno4ka [110]
1 step: S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}, S_{3}=T_{1}+T_{2}+T_{3}, then
 S_{5}-S_{3}=T_{4}+T_{5}=5.

2 step: T_{n}=T_{1}*q^{n-1}, then 
T_{6}=T_{1}*q^{5}
T_{5}=T_{1}*q^{4}
T_{4}=T_{1}*q^{3}
T_{3}=T_{1}*q^{2}
and \left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right. will have form \left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right..

3 step: Solve this system  \left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right. and dividing first equation on second we obtain \frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}. So, \frac{(q-1)(q+1)}{q+1} = \frac{1}{2} and q-1= \frac{1}{2}, q= \frac{3}{2} - the common ratio.

4 step: Insert q= \frac{3}{2}into equation T_{1}*q^{3}*(q+1)=5 and obtain T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5, from where T_{1}= \frac{16}{27}.




5 0
3 years ago
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