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alexira [117]
3 years ago
11

Help please with this fast

Mathematics
1 answer:
nikdorinn [45]3 years ago
5 0
The answer is 120 to find mt
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Answer the questions attached about the given sequence: -33, -27, -21, -15, ...
Arte-miy333 [17]

Answer:

see below

Step-by-step explanation:

-33, -27, -21, -15,....

-33 +6 = -27  

-27+6 = -21

-21+6 = -15

This is an arithmetic sequence

The common difference is +6

explicit formula

an=a1+(n-1)d  where n is the term number and d is the common difference

an = -33 + ( n-1) 6

an = -33 +6n -6

an = -39+6n

recursive formula

an+1 = an +6

10th term

n =10

a10  = -39+6*10

      = -39+60

      =21

sum formula

see image

The sum will diverge since we are adding infinite numbers

7 0
3 years ago
For questions 1 - 2, use the following functions:
natita [175]

Answer:

fx+gx=5x-11

fx-gx=x-3

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help me !??!!!
iris [78.8K]

Answer:

X =0

Step-by-step explanation:

divide each term by 15 and simp

4 0
3 years ago
11th grade geometry:
Aliun [14]

Answer:

<em>The perimeter is 72 units and the area is 149 square units.</em>

Step-by-step explanation:

\triangle SBA has coordinates S(15,-8),B(-2,21) and A(0,0)

Using the distance formula.........

Length of side SB = \sqrt{(15+2)^2+(-8-21)^2}= \sqrt{17^2+(-29)^2}= \sqrt{1130}

Length of side BA= \sqrt{(-2)^2+(21)^2}= \sqrt{445}

Length of side AS =\sqrt{(15)^2+(-8)^2}=\sqrt{289}=17

So, the perimeter of the triangle will be:  (SB+BA+AS)= \sqrt{1130}+ \sqrt{445}+17 =71.71... \approx 72 units.   <em>(Rounded to the nearest unit)</em>

The height of the triangle for the corresponding base SB is 8.89 units.

<u>Formula for the Area of triangle</u>,  A= \frac{1}{2}(base\times height)

So, the area of the \triangle SBA will be:  \frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149 square units.   <em>(Rounded to the nearest unit)</em>

3 0
3 years ago
The sum of two numbers is equal to 70. Which of the following functions can be use to find the product of the two numbers if one
Temka [501]
Let x=number 1 let y=number2
there sum is equal to 70
then

number1+number2=70

substituting

x+y=70

y=70-x
let there product will be p
p=xy
substituting
p=x(70-x)
which is choice c

4 0
3 years ago
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