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2 years ago

The pre-image and image of what transformation are not congruent?

Mathematics

1 answer:

ad-work [718]2 years ago

6 0

Answer:

Option A

Step-by-step explanation:

Options B, C, and D are examples of ridged transformations. Ridged transformations are transformations that keep the pre-image and image congruent.

A dilation would change the actual size of the pre-image to make the image, so they would be not congruent in a dilation.

Hope this helps.

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Which pair of angles are supplementary?

Lina20 [59]

Supplementary angles are angles that add up to 180 degrees, aka one straight line. The supplementary angles here are:

1 and 2, 1 and 3, 2 and 4, 3 and 4, 5 and 6, 6 and 8, 7 and 8, and 6 and 7. Well, those are the more obvious ones. 1 and 7 are supplementary because if you envision them next to each other, you’ll see that they create a straight line. So, with that logic, 3 and 5 are supplementary because when you put them together, they create a straight line

3 0

3 years ago

Wesley earned $72 walking dogs for 6 hours. How many total hours will it take Wesley to earn $96 in all? Solve using unit rates.

MissTica

8 hours

72/6=12 $12 and hour 96/12=8 8 hours to earn $96

8 0

2 years ago

I will give brainliest

allochka39001 [22]

Answer:

1) Yes 2)No

Step-by-step explanation:

1) Yes because the two shorter lines combined are longer than the base and so those two lines are able to make a triangle.

2) No because the two lines on top will be equal to base line and so the two shorter lines will not be able to make a third angle because it will be level with the base.

4 0

3 years ago

A candy company claims that 20% of the candies in its bags are colored green. Steve buys 30 bags of 30 candies, randomly selects

Allisa [31]

Answer:

The probability of Steve agreeing with the company’s claim is 0.50502.

Step-by-step explanation:

Let X denote the number of green candies.

The probability of green candies is, p = 0.20.

Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.

So, n = 30 candies are randomly selected.

All the candies are independent of each other.

The random variable X follows a binomial distribution with parameter n = 30 and p = 0.20.

It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.

Compute the probability of 5, 6 and 7 green candies as follows:

$P(X=5)={30\choose 5}(0.20)^{5}(1-0.20)^{30-5}=0.17228\\\\P(X=6)={30\choose 6}(0.20)^{6}(1-0.20)^{30-6}=0.17946\\\\P(X=7)={30\choose 7}(0.20)^{7}(1-0.20)^{30-7}=0.15328$

Then the probability of Steve agreeing with the company’s claim is:

P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)

= 0.17228 + 0.17946 + 0.15328

= 0.50502

Thus, the probability of Steve agreeing with the company’s claim is 0.50502.

7 0

3 years ago

En la división sintética sólo son tomados en cuenta los coeficientes del divisor?

Airida [17]

La división sintetica sirve para el cociente entre polinomios, la cual es particularmente util para cuando tenemos un numerador de grado alto y un denominador de grado 1.

Veremos que si, en la división sintética solo son tomados en cuenta los coeficientes del divisor.

Para explicarla, usaremos un ejemplo.

x^3 - 2x^2 + 5x + 3 será el numerador

x - 2 será el denominador.

Para poder aplicar la división sintetica, el maximo exponente en el denominador debe ser uno.

Así, nuestro cociente es:

$\frac{x^3 - 2x^2 + 5x + 3}{x-2}$

Procedemos a igualar el denominador a cero:

x - 2 = 0

x = 2

Ahora veremos los coeficientes del numerador (el numerador es el divisor).

Lo que debemos hacer es tomar cada coeficiente (comenzando por los que multiplican a los terminos con mayor exponente) y multiplicarlos por este número.

En este caso, el primer coeficiente es 1.

2*1 = 2

Ahora le sumamos esto al proximo coeficiente, que es -2:

-2 + 2 = 0

Multiplicamos esto por el valor de x, que es 2.

2*0 = 0

Ahora sumamos esto al proximo coeficiente, que es 5

5 + 0 = 5

Multiplicamos esto por el valor de x, que es 2:

5*2 = 10

Sumamos esto al ultimo coeficiente, que es 3.

10 + 3 = 13

Este ultimo valor es el residuo, y los primeros 3 números que obtuvimos son los coeficientes del cociente, entonces el cociente será:

1*x^2 + 0*x + 10 = x^2 + 10

Como vimos, solo usamos los coeficientes del numerador/divisor para realizar esta operación, por lo que si, solo los coeficientes del divisor son tomados en cuenta.

Si quieres aprender más, puedes leer:

brainly.com/question/10466403

3 0

2 years ago