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3 years ago

Find the area of the given figure.

Mathematics

2 answers:

marissa [1.9K]3 years ago

6 0

84.6 km2 is the answer

Lerok [7]3 years ago

3 0

The answer would definitely be be 84.6 km2, hopefully.

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Someeee one?????????????????

Ad libitum [116K]

Answer:

Option B) $a_{n} = 2\cdot 4^{n-1}$

Step-by-step explanation:

The given geometric sequence is

2, 8, 32, 128,....

The general form of a geometric sequence is given by

$a_{n} = a_{1}\cdot r^{n-1}$

Where n is the nth term that we want to find out.

a₁ is the first term in the geometric sequence that is 2

r is the common ratio and can found by simply dividing any two consecutive numbers in the sequence,

$r=\frac{8}{2} = 4$

You can try other consecutive numbers too, you will get the same common ratio

$r=\frac{32}{8} = 4$

$r=\frac{128}{32} = 4$

So the common ratio is 4 in this case.

Substitute the value of a₁ and r into the above general equation

$a_{n} = 2\cdot 4^{n-1}$

This is the general form of the given geometric sequence.

Therefore, the correct option is B

Note: Don't multiply the first term and common ratio otherwise you wont get correct results.

Verification:

$a_{n} = 2\cdot 4^{n-1}$

Lets find out the 2nd term

Substitute n = 2

$a_{2} = 2\cdot 4^{2-1} = 2\cdot 4^{1} = 2\cdot 4 = 8$

Lets find out the 3rd term

Substitute n = 3

$a_{3} = 2\cdot 4^{3-1} = 2\cdot 4^{2} = 2\cdot 16 = 32$

Lets find out the 4th term

Substitute n = 4

$a_{4} = 2\cdot 4^{4-1} = 2\cdot 4^{3} = 2\cdot 64 = 128$

Lets find out the 5th term

Substitute n = 5

$a_{5} = 2\cdot 4^{5-1} = 2\cdot 4^{4} = 2\cdot 256 = 512$

Hence, we are getting correct results!

6 0

3 years ago

Which graph shows the line y-1=2(x+2)

Yanka [14]

Graph C. The equation of the line is y=2x+5. 5 is the y-intercept so the line has to go through that point.

3 0

3 years ago

Read 2 more answers

Please show your work

Effectus [21]

Here hope this help the solution is X= -2 and y=9

4 0

2 years ago

1. the sum of five times a number and -2, added to seven times the number

emmasim [6.3K]

1. (5x - 2) + 7x = 12x - 2

2. 6(x - 5) > 22
6x - 30 > 22
6x > 52
x > 52/6
x > 26/3

7 0

2 years ago

Where is (0,19) located? Quadrant I Quadrant II Quadrant III Quadrant IV X-axis Y-axis

12345 [234]

Let P(a, b) be a point on the coordinate plane. Then the following hold:

i) If a>0, b>0 then P is in the I.Quadrant.

ii) If a<0, b>0 then P is in the II.Quadrant.

iii) If a<0, b<0 then P is in the III.Quadrant.

iv) If a>0, b<0 then P is in the IV.Quadrant.

v) If a=0 and b is positive or negative, then P is on the y-axis.

vi) If b=0 and a is positive or negative, then P is on the x-axis.

Since we have: a=0, and 19 positive, then this point is on the y-axis.

Answer: y-axis

5 0

3 years ago