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Aleksandr [31]
4 years ago
12

Consider the following equations.

Mathematics
1 answer:
DENIUS [597]4 years ago
4 0

Answer:

Please, see the image below.

Step-by-step explanation:

I attached an image of the sketched region below.

You take into account that y=0 is the x axis.

Furthermore, you take into account that f(x)=-5x^3 is, for x=-2 and x=-1:

f(-2)=40

f(-1)=5

Finally, the region bounded by the equations is above the negative x axis.

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Which of the following represents a geometric sequence? I 1/4, 1/4, 1/4, 1/4 II 1/4, 1/5, 1/6 III 1/4, 1, -4, 1/6 IV 1/4, -4, 1/
LenaWriter [7]
I'm pretty sure it would be none of these because1/4*5=1 and 1/4 then it would be 6 and 1/4 then it would be 31 and 1/4
7 0
3 years ago
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You have averaged $62,500.00 for the last five years of work. your company has agreed to pay you a yearly pension of 75 %. what
fenix001 [56]
$600,400,145..........
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3 years ago
An employee receives a weekly salary of $340 and a 6% commission on all sales.
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340+.06(sales)
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3 years ago
The length of a rectangle is five times it’s width if the area of the rectangle is 320m^2 find its perimeter
BlackZzzverrR [31]

Answer:

Perimeter of the rectangle = 96 meters.

Step-by-step explanation:

Let the width of the rectangle = K

So, the length of the rectangle = 5K

Area  = 320 sq meters

Now, Area of a Rectangle  = Length x Width

⇒  320  = K x  5K

or,5K^{2} = 320\\or, K^{2}  = \frac{320}{5}   = 64

So, the vlue of K = 8 or, K = -8

But as K represents a length hence, K ≠ -8

So, the <u>width of the rectangle = 8 meters</u>

and the<u> length  of the rectangle = 8 x 5 = 40 meters</u>

Now, Perimeter = 2(length + width)

                            = 2(8 + 40) = 96 meters.

So, the perimeter of the rectangle = 96 meters.

6 0
3 years ago
Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.
galina1969 [7]

Answer:

All potential roots are 3,3 and -\frac{5}{3}.

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

f(x)=3x^3-13x^2-3x+45

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45

q=\pm 1,\pm 3

All possible roots

\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}

Now we check each rational root and see which are possible roots for given function.

f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0

f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32

f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144

f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}

Similarly, we will check for all value of p/q and we get

f(-5/3)=0

Thus, All potential roots are 3,3 and -\frac{5}{3}.


5 0
3 years ago
Read 2 more answers
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