Answer:
Step-by-step explanation:
57 lb bag for $ 11 or 1 lb bag for $ 0.41
11/51 = 0.215 .....rounds to 0.22 ......this is the correct way...... the student messed up and divided wrong.
the large bag only charges $ 0.22 per lb, whereas, the small bag charges $ 0.41 per lb.
There are 8 women and 3 awards. 8×3=24. B. 24 Ways.
<h3>Given:</h3>
The ratio of number of girls and boys in a class of 30 students is 7:8
<h3>To Find:</h3>
The ratio of number of girls and boys if 5 new boys admit in the class.
<h3>Assumption:</h3>
Let the number of students be x.
<h3>Solution:</h3>
According to the question,
7x + 8x = 30
or, 15x = 30
or, x = 
or, x = 2
7x = 7(2) = 14
8x = 8(2) = 16
There were 14 boys and 16 girls in the school.
After admitting 5 new boys, we get
14 + 5 = <u>19</u>
The ratio of number of girls and boys now is 16:19.
<h2>Answer:</h2>
<u>1</u><u>6</u><u>:</u><u>1</u><u>9</u>
Answer:
a) dx/dt = kx*(M - h/k - x)
Step-by-step explanation:
Given:
- The harvest differential Equation is:
dx/dt = kx*(M-x)
Suppose that we modify our harvesting. That is we will only harvest an amount proportional to current population.In other words we harvest hx per unit of time for some h > 0
Find:
a) Construct the differential equation.
b) Show that if kM > h, then the equation is still logistic.
c) What happens when kM < h?
Solution:
- The logistic equation with harvesting that is proportional to population is:
dx/dt = kx*(M-x) hx
It can be simplified to:
dx/dt = kx*(M - h/k - x)
- If kM > h, then we can introduce M_n=M -h/k >0, so that:
dx/dt = kx*(M_n - x)
Hence, This equation is logistic because M_n >0
- If kM < h, then M_n <0. There are two critical points x= 0 and x = M_n < 0. Since, kx*(M_n - x) < 0 for all x<0 then the population will tend to zero for all initial conditions
