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3 years ago

Which shows an explicit formula for a sequence whose first term is 8 and

Mathematics

1 answer:

DochEvi [55]3 years ago

5 0

Answer:

7n + 1

Step-by-step explanation:

the general formula for figuring out the formula of a sequence is a + (n - 1)d, where a = the first term and d = the common difference

The question tells u that the first term is 8 and the common difference is 7

Knowing this, you can substitute those values into the formula and simplify:

a + (n - 1)d

= 8 + (n - 1)*7

= 8 + (7n -7)

= 8 + 7n - 7

= 7n - 7 + 8

= 7n + 1

and there's your explicit formula! hope this helped!

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Question 9 Multiple Choice Worth 1 points)

beks73 [17]

Answer: $\bold{10 = \sqrt {\left( {x- 8 } \right)^2 + \left( {y - 9 } \right)^2 }}$

Step-by-step explanation:

<u>Given:</u>

The coordinates of Point A: (8, 9)

The coordinates of Point B are unknown: (x, y)

The distance from A to B is 10 units

Then, using the distance formula:

$AB = \sqrt {\left( {x- 8 } \right)^2 + \left( {y - 9 } \right)^2 }$

Therefore,

$10 = \sqrt {\left( {x- 8 } \right)^2 + \left( {y - 9 } \right)^2 }$

8 0

2 years ago

50 POINTS SOLVE !! ::

satela [25.4K]

Answer:

Step-by-step explanation:

<u>k - 4</u> = 3

k/9 = 3(9) + 4

k = 31/9

k = 31/9

<u>8 + b </u> = -5

-4

8 + b = -5 (-4)

8 + b = 20

b = 20 - 8

b = 12

4 0

3 years ago

Please help will mark brainliest

asambeis [7]

The total cost of the tent is 409.86

------------------------------------------------------

explanation:

230×0.65=149.50

230+149.50=379.50×.08=30.36

379.50+30.36=409.86

(Hope this helps :) )

5 0

2 years ago

Read 2 more answers

If P(C)=.29, P(D)=.47 and P(C and )= 0, are the events C and D mutually exclusive? Find P(C or D)

abruzzese [7]

Answer:

Step-by-step explanation:

note : P(C or D) = P(C)+P(D) - P(C and )

P(C or D) =0.29+0.47- 0

P(C or D) = 0.76

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3 years ago

Sin^2(x/2)=sin^2x <br> Find the value of x

Veronika [31]

$\sin^2\dfrac x2=\sin^2x$
$\dfrac{1-\cos x}2=1-\cos^2x$
$1-\cos x=2-2\cos^2x$
$2\cos^2x-\cos x-1=0$
$(2\cos x+1)(\cos x-1)=0$
$\implies\begin{cases}2\cos x+1=0\\\cos x-1=0\end{cases}$ $\implies\begin{cases}\cos x=-\frac12\\\cos x=1\end{cases}$

The first case occurs in $0\le x$ for $x=\dfrac{2\pi}3$ and $x=\dfrac{4\pi}3$ . Extending the domain to account for all real $x$ , we have this happening for $x=\dfrac{2\pi}3+2n\pi$ and $\dfrac{4\pi}3+2n\pi$ , where $n\in\mathbb Z$ .

The second case occurs in $0\le x$ when $x=0$ , and extending to all reals we have $x=2n\pi$ for $n\in\mathbb Z$ , i.e. any even multiple of $\pi$ .

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3 years ago