Answer:
Area of the region = 15.03 in²
Step-by-step explanation:
Area of region between a regular hexagon with sides 6" and circle inscribed.
So Area of region = Area of regular hexagon - area of circle
Now area of regular hexagon = 
where a = side of the hexagon = 6"
Now area of regular hexagon = 
= 93.53 square in.
Area of circle inscribed = πr²
Here r is the radius of the circle = 
r = 5"
So area of the inscribed circle = π(5)² = 3.14(25) = 78.5 square in.
Now area of region = 93.53 - 78.5 = 15.03 in²
6x+21+15-2x
4x+36
hope this helps...
Answer:
136 
Step-by-step explanation:
Well if you find the lateral area (the area of the rectangles on the sides) to get 112, so you just need to add that to the triangles and for those (they add up to 36) you can just use the formula for the area of a triangle, which is 
.
Hope this helps :)
Hello from MrBillDoesMath!
Answer: SAS = side - angle -side congruence
SSS = side - side - side congruence
Discussion
:
In Plane Geometry, identical triangles are said to be "congruent". There are several ways, depending upon the information you have, to prove 2 triangles are congruent.
In one approach ("SSS") if you can show that 2 triangles have identical side lengths, then the triangles are congruent. (A triangle has 3 sides, hence "SSS" -- 3 S's; 3 sides, get it?)
In another approach ("SAS") if you can show that 2 sides, and the angle included between those sides, in one triangle are identical to the sides and included angle in another triangle, then the triangles are congruent
It's easier to understand this with a picture or diagram than in words. Please review the SSS, SAS picture in your textbook
Regards, MrB
Answer: x=1001, -999
Step-by-step explanation:
I hope that this helps sum
