Answer:
<h2>The year is 2010.</h2>
Step-by-step explanation:
The population of wolves is given by P(t) = 80(0.98)t.
The study has began in the year of 2000 and will end in 2020.
The difference between 2000 and 2009 is 9 years and the difference between 2009 and 2020 is 11 years.
Hence, the maximum value of t is 11.
The domain is 
.
The population will be 80, that is P(t) = 80.
Hence, 0.98t = 1, or, t = 
≅1.
In (2009 + 1) = 2010, the population of wolves will be 80.
Question 4 is d question 3 is c
After you've calibrated the sprayer to know your application rate in gallons per acre, divide that number into the gallons applied with each tankful to find how many acres each tankful covers. Then, multiply the acres per tank by the herbicide needed per acre to find the herbicide to put in each tankful.
Mark me as brainliest please
1 dimes are worth 10 cents.
Multiply.
6 * 10 = 60
Put in a fraction with the denominator given.
60/100
Reduce the fraction.
60/100
30/50
15/25
3/5
Best of Luck!
