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kupik [55]
3 years ago
9

Find the volume of each figure. Round to the nearest tenth if needed.​

Mathematics
1 answer:
Romashka [77]3 years ago
5 0

Answer:

2309.07 ft

Step-by-step explanation:

The formula for finding volume of a cylinder is V = πr^2*h. You can plug in your radius, which is 7, and your height, which is 15. This gives you 735π, or 2,309.07.

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(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

In point 1:

The Reflexive closure:  

Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is  (0,0),(1,1),(2,2) \ and \ (3,3)

Thus, the reflexive closure: R={(0,0),(0,1),(1,1),(1,2),(2,0),(2,2),(3,0), (3,3)}

In point 2:

The Symmetric closure:

R relation symmetrically closes by adding(b,a) to R for each (a,b) of R  Therefore, here (b,a) is:   (0,1),(0,2)\ and \ (0,3)

Thus, the Symmetrical closure:

R={(0,1),(0,2),(0,3)(1,0),(1,1)(1,2),(2,0),(2,2),(3,0), (3,3)}

8 0
3 years ago
Which expression is equivalent to<br> 4x + ?<br> o 1(-x+2)<br> o 1(-2+ 3)<br> -1(-x+ )<br> - (x + 2)
slavikrds [6]

Answer:

Definitely Option A.

When you expand the bracket of Option A... You have your equation

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7 0
3 years ago
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Answer:

y = 22

Step-by-step explanation:

we want to move the -8 to the other side, so 14+8 = 22

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Answer:

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Step-by-step explanation:

The relationship occurs because having two congruent Pentagons and generating a segment within them (or outside), congruence is extrapolated to the triangles generated within them. Thus, if there is congruence among the pentagons, it will exist between the formed triangles. In other words since the two pentagons are congruent, the corresponding angle pair is congruent. also the two corresponding side pairs are also congruent.

In the attached image for example, the ABCDE and KLMNO pentagons are congruent, so all of their internal division lines are also congruent (AC and KM)

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