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rodikova [14]
3 years ago
9

What is the equation of this line?

Mathematics
1 answer:
yuradex [85]3 years ago
8 0

Answer

y= -7

Because when x= 1, y= -7, when x= 2, y=-7. So it will always be y=-7 for how long x extends

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4) −4b + 3 = 35 <br> solve equation
rosijanka [135]

Answer:

-8

Step-by-step explanation:

when you substitute -8 for b it is -4(-8)+3=35

-4(-8) is 32 and 32+3=35

Boom.

also btw need help give brainliest

5 0
3 years ago
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Please help! Identify each decimal number as either rational or irrational.
labwork [276]

Answer:

A Rational number is a number that can be written as a ratio in fraction form.

An Irrational number is a number that, when in decimal form, does not terminate or repeat.

Step-by-step explanation:

1.485 can be written as 1 485/1000 - it is rational

0.187345911... continues on and does not repeat - it is irrational

333.051422218... continues on and does not repeat - it is irrational

0.2268715 can be written as 2268715/10000000 - it is rational

1.24 can be written as 1 24/100 - it is rational

6 0
3 years ago
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Nastasia [14]
Sorry very hard to ans btw gl
8 0
1 year ago
Find the selling price of each item.<br> 57) Original price of a puppy: 339.50<br> Discount: 55
densk [106]

Answer:

The selling price of the puppy is $284.50.

Step-by-step explanation:

In the present case, the puppy's original selling price is $ 339.50. At this price a discount of $ 55 is made, that is, that amount is subtracted from the original price, modifying the sale price.

Therefore, since 339.50 - 55 results in 284.50, the puppy's sale price goes from $ 339.50 to $ 284.50, taking the aforementioned discount.

5 0
2 years ago
Construct a 90% confidence interval for μ1-μ2 with the sample statistics for mean calorie content of two​ bakeries' specialty pi
DIA [1.3K]

Answer:

The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (<u>49</u>) < μ₁ - μ₂ < (<u>289)</u>

Step-by-step explanation:

The given data are;

Bakery A

\overline x_1<em> </em>= 1,880 cal

s₁ = 148 cal

n₁ = 10

Bakery B

\overline x_2<em> </em>= 1,711 cal

s₂ = 192 cal

n₂ = 10

\left (\bar{x}_1-\bar{x}_{2}  \right ) - t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2}  \right ) + t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}

df = n₁ + n₂ - 2

∴ df = 10 + 18 - 2 = 26

From the t-table, we have, for two tails, t_c = 1.706

\hat{\sigma} =\sqrt{\dfrac{\left ( n_{1}-1 \right )\cdot s_{1}^{2} +\left ( n_{2}-1 \right )\cdot s_{2}^{2}}{n_{1}+n_{2}-2}}

\hat{\sigma} =\sqrt{\dfrac{\left ( 10-1 \right )\cdot 148^{2} +\left ( 18-1 \right )\cdot 192^{2}}{10+18-2}}= 178.004321469

\hat \sigma ≈ 178

Therefore, we get;

\left (1,880-1,711  \right ) - 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}< \mu _{1}-\mu _{2}< \left (1,880-1,711  \right ) + 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}

Which gives;

169 - \dfrac{75917\cdot \sqrt{35} }{3,750} < \mu _{1}-\mu _{2}< 169 + \dfrac{75917\cdot \sqrt{35} }{3,750}

Therefore, by rounding to the nearest integer, we have;

The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289

4 0
3 years ago
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