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3 years ago

PLEASE HELP MEEEEE (using 98 points to post)

Chemistry

2 answers:

Alla [95]3 years ago

8 0

29.2 g/mol is your answer

Gekata [30.6K]3 years ago

7 0

Δt = i Kf m

2.86 °C = (1) (1.86 °C kg mol-1) (x / 0.750 kg)

2.86 °C = (2.48 °C mol-1) (x)

x = 1.1532 mol

33.7 g / 1.1532 mol = 29.2 g/mol

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I need help with this packet

Anna11 [10]

Q1. An inorganic compound is a compound where the main constituent or substance is not that of Carbon but predominantly other elements, such as I, N etc. An organic compound is one where the main substituent or main element, the element found in much greater amounts would be Carbon.

Q2. Water is considered a very good solvent, because of its ability to dissolve well with mostly all other polar compounds, and produce ions from those ionic compounds.

A. Hydrogen atoms
B. Oxygen atom.

5 0

3 years ago

What is the maximum amount in moles of P2O5P2O5 that can theoretically be made from 112 gg of O2O2 and excess phosphorus

Nastasia [14]

Answer:

$n_{P_2O_5}^{max}=1.4molP_2O_5$

Explanation:

Hello!

In this case, since the reaction between phosphorous and oxygen to form diphosphorous pentoxide is:

$2P+\frac{5}{2}O_2\rightarrow P_2O_5$

Thus, since phosphorous is in excess and oxygen and diphosphorous pentoxide are in a 5/2:1 mole ratio, we can compute the maximum moles of product as shown below:

$n_{P_2O_5}^{max}=112 gO_2*\frac{1molO_2}{32.00gO_2}*\frac{1molP_2O_5}{5/2molO_2}\\\\ n_{P_2O_5}^{max}=1.4molP_2O_5$

Best regards!

5 0

3 years ago

A balloon originally had a volume of 4.39 L at 44C and a pressure of 729 torr to what temperature must the balloon be cooled

VMariaS [17]

The new temperature : 11.56 °C

<h3>Further explanation </h3>

Boyle's law and Gay Lussac's law

$\tt \dfrac{P_1.V_1}{T_1}=\dfrac{P_2.V_2}{T_2}$

P1 = initial gas pressure (N/m² or Pa)

V1 = initial gas volume (m³)

P2 = final gas pressure

V2 = final gas volume

T1 = initial gas temperature (K)

T2 = final gas temperature

V₁=4.39 L

T₁=44+273=317 K

P₁ = 729 torr = 0,959211 atm

V₂=3.78 L

P₂= 1 atm

$\tt \dfrac{0.959211\times 4.39}{317}=\dfrac{1\times 3.78}{T_2}\\\\T_2=\dfrac{1\times 3.78\times 317}{0.959211\times 4.39}\\\\T_2=284.559~K=11.56~C$

3 0

3 years ago

what is the molar mass of a gaseous flouride of sulfur containing 70.4% F and having a density of approximately 4.5g/L at 20 deg

zlopas [31]

Answer:

The molar mass is 180.2 g/mol

Explanation:

Step 1: Data given

% of F = 70.4 %

Density = 4.5 g/L

Temperature = 20 °C

Pressure = 1 atm

Step 2: Calculate the number of moles

PV = nRT

⇒ with P = the pressure = 1.00 atm

⇒ with V = the volume = Assume this is 1L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature : 20°C = 293 Kelvin

1 atm*1L= n(0.08206 L-atm/mol-K)*(293 K)

n = 0.04159 moles

Step 3: Calculate molar mass

Molar mass = Mass / moles

4.5 grams / 0.04159 moles = 108.2 g/mol

Step 4: Calculate moles of F

Moles = Mass / molar mass

Moles F = 70.4 g / 19 g/mol

Moles F = 3.70 moles

Moles S = 29.6g / 32.07 g/mol

Moles S = 0.923 moles S

Step 5: Divide by the smallest amount of moles

F = 3.70 / 0.923 = 4

S = 0.923 / 0.923 = 1

The empirical formula is SF4

The molar mass of SF4 = 32.07 + 4*19 = 108.07 g/mol

This means the empirical formula is the same as the molecular formula SF4

The molar mass is 180.2 g/mol

4 0

3 years ago

If you try to place the compound on the pan over the flame, what could possibly happen? Explain your answer. [2 marks] anyone pl

Scilla [17]

Answer:

it will probably flame up or explode or maybe start boiling

8 0

3 years ago