<h3>The <u>
complete question</u>
would be:</h3>
In a common laboratory experiment in general chemistry, students are asked to determine the relative amounts of benzoic acid and charcoal in a solid mixture. Benzoic acid is relatively soluble in hot water, but charcoal is not. Devise a method for separating the two components in the mixture.
<h3>The <u>
solution</u> for that would be:</h3>
First you put the mixture in hot water and allow the benzoic acid to separate. Next funnel it and then see what's on the funnel paper. Lastly, heat the leftover water and see what's left after it evaporates.
<h3><u>What are laboratory experiments ?</u></h3>
- Using controlled surroundings to test theories, researchers may develop laboratory experiments.
- Laboratories are rooms or specially constructed facilities within buildings that are often found on college and university campuses and are utilized for academic research.
- It's crucial to differentiate between experiments and other kinds of research investigations carried out in lab settings.
- Even if a research study takes place in a lab, it is not always an experiment.
- In order to evaluate causal conclusions regarding the links between independent and dependent variables, laboratory studies, like all genuine experimental designs, use procedures of random assignment of participants and control groups.
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The rcf (recipe conversion factor)= 0.6
<h3>What is the rcf (recipe conversion factor)?</h3>
- The conversion factor approach is the most typical technique for modifying recipes.
- Finding a conversion factor and multiplying the ingredients in the original recipe by that factor are the only two steps needed to do this.
- Remember that the conversion factor will be larger than 1 if you are raising your amounts to be sure you are finding it correctly.
- The factor will be less than 1 if your amounts are being decreased. Use the conversion factor approach if you come across a recipe that is written in a standard format.
- The production of phenolic monomers from lignin is effective and selective when done using reductive catalytic fractionation (RCF).
How this is calculated?
Conversion Factor = New Yield ÷ Old Yield
=80/134
=0.5970
=0.6(rounded to nearest tenth)
To know more about the recipe conversion factor (RCF),refer:
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Answer:
hey there
Explanation:
CN- (aq) + H+ (aq) → HCN(I)
The reactants are aqueous solutions:
NaCN(aq) and HBr(aq)
When you mix these compounds you make pure HCN (I)
The molecular equation is:
NaCN(aq) + HBr(aq) → NaBr(aq) + HCN(I)
When you dissociate the reactants, you have: Nat(aq) +CN¯(aq) + H*(aq) + Br−(aq) → Nat(aq) + ->
Br (aq) + HCN(I)
Sodium bromide, it is a salt, that can also be
dissociated in the solution
To make, the net ionic equation you remove the repeated ions
CN- (aq) + H+ (aq) → HCN(I)
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