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Tamiku [17]
3 years ago
11

What are the steps to solve

title=" \sqrt{20 {k}^{3} } " alt=" \sqrt{20 {k}^{3} } " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
vlada-n [284]3 years ago
3 0
\bf \sqrt{20k^3}\qquad 
\begin{cases}
20=2\cdot 2\cdot 5\\
\qquad 2^2\cdot 5\\
k^3=k^{2+1}\\
\qquad k^2\cdot k^1
\end{cases}\implies \sqrt{2^2\cdot 5\cdot k^2\cdot k}\implies 2k\sqrt{5k}
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Solve for y.<br> 2x-3y=9
cluponka [151]

Answer:

y = 2/3x - 3

Step-by-step explanation:

Step 1: Write equation

2x - 3y = 9

Step 2: Solve for <em>y</em>

  1. Subtract 2x on both sides: -3y = 9 - 2x
  2. Divide both sides by -3: y = -3 + 2/3x
  3. Rewrite: y = 2/3x - 3
6 0
3 years ago
Plz help me solve it the question is below
AlladinOne [14]

Answer:

\frac{1024}{2025}

Step-by-step explanation:

\frac{3}{4}^{-4}  = \frac{1}{\frac{3}{4}^{4}  }

(3/4)^4 = 81/256

1 ÷  81/256 = 256/81

So;

\frac{256}{81} * \frac{4}{9} = \frac{1024}{729}

\frac{1024}{729} / n = \frac{1}{9/25}

\frac{1024}{729n} = \frac{25}{9} \\\\n = \frac{1024 *9 }{25 * 729}  = \frac{1024}{2025}

6 0
3 years ago
Please help ASAP.. I don’t understand.
Dmitry_Shevchenko [17]

Y intercept means x = 0, on x= 0 y is also zero so the cordinate is (0,0)

8 0
3 years ago
Help pls if u can..<br><br><br><br> thanks!
GREYUIT [131]

Answer:

A) Rational

B) Irrational

C) Rational

D) Irrational

Step-by-step explanation:

Irrational numbers cannot be expressed as a ratio of two number, whereas rational numbers can be. 81 can be expressed as 9*9 whereas, 89 cannot be expressed as ratio of two numbers.

3 0
2 years ago
2(x+x+12) &gt; 100 (why does the 20 character thing exist)
arlik [135]

Answer:

x > 19

Step-by-step explanation:

2(x+x+12) > 100

 2(2x+12) > 100

     4x+24 > 100

           4x > 76

              x > 19

3 0
2 years ago
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