Answer:
We have;
7 pencil boxes and 5 eraser boxes
Step-by-step explanation:
To find the smallest number of boxes that can be bought, what we simply do is to find the lowest common multiple of the content of each of the boxes
hence, we are going to find the lowest common multiple of 10 and 14
The lowest common multiple of 10 and 14 is 70
So the smallest number of pencil boxes that can be bought is 70/10 = 7
The smallest number of eraser boxes would be 70/14 = 5
53,000 or 50,000 depending on how precisely you want to estimate
Answer:
x=340
y=-165
Step-by-step explanation:
x/10+y/5=1 Equation 1
x/8+y/6=15 Equation 2
Using elimination method, we multiply equation 1 by 1/6, the coefficient of y in equation 2 and then also multiply equation 2 by 1/5, the coefficient of y in equation 1, this will make you have the same coefficient and then easy to eliminate.
1/6(x/10+y/5=1)
x/60+y/30=1/6 Equation 3
1/5(x/8+y/6=15)
x/40+y/30=15/5
x/40+y/30=3 Equation 4
We subtract equation 3 from equation 4 to eliminate y
x/40-x/60= (3x-2x)/120= x/120
y/30-y/30
3-1/6= (18-1)/6= 17/6
We now have
x/120=17/6
Cross multiply
6x=2040
Divide both sides by 6
6x/6=2040/6
x=2040/6
x=340
Substitute x for 340 in equation 1
x/10+y/5=1
340/10+y/5=1
34+y/5=1
y/5=1-34
y/5=-33
Cross multiply
y=-33(5)
y=-165
Answer:
9.42 ft
Step-by-step explanation: