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Helen [10]
3 years ago
13

(7 x 18 + 45) : 3 x 2 what is it please?​

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
7 0

The Answer Is 171 : 6

Hope This Help's

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Solve y = x + 8 for x.<br> x = y + 8<br> x = y - 8<br> X = -y + 8<br> X = -V +8
JulijaS [17]

Answer:

y = x + 8

Step-by-step explanation:

7 0
2 years ago
Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)
USPshnik [31]

First, expand the terms inside the bracket you will get

(( \tan {}^{2} (x)  + 2 \tan(x)  \sin(x)  +  \sin {}^{2} (x)  - ( \tan {}^{2} (x)  - 2 \tan(x)  +  \sin {}^{2} (x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

( 4 \tan(x)  \sin(x) ) {}^{2}  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x)  \sin {}^{2} (x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16 \tan {}^{2} (x) (1 -  \cos {}^{2} (x) ) = 16 (\tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan {}^{2} (x)  -   \frac{  \sin {}^{2} (x) \cos {}^{2} ( {x}^{} )  }{ \cos {}^{2} (x) }

16( \tan {}^{2} (x)  -  \sin {}^{2} (x) ) = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x)  = 16( \tan(x)  +  \sin(x) )( \tan(x)  -  \sin(x) )

5 0
2 years ago
EMERGENCY (NEED HEP NOW!!!)
diamong [38]

Answer:

x=-2.25,y=-2.25

Step-by-step explanation:

The given system is

4x - y =  - 9 \\ 3x - 3y = 0

We want to solve the system for x and y that makes the system true.

Let us multiply the first equation by 3 while maintaining the second equation:

12x -3 y =  - 27 \\ 3x - 3y = 0

Subtract the current second equation from the first one.

12x =  - 27

Divide through by 12:

x =  -  \frac{27}{12}  =  - 2.25

From the second equation we have:

3x = 3y

This implies that:

x = y =  - 2.25

8 0
3 years ago
A loan of $900 will be repaid in 36 installment of $30.22 each .what is the finance charge for the loan
Marat540 [252]

i hope this is what you are looking for but 36 times 30.22 equals 1087.92 subtract from 900 which is $187.92

<h2>$187.92 for finance charge for loan</h2>
8 0
3 years ago
Is a/b +b/c rational number<br>​
Anarel [89]

Answer:

Yes.

Step-by-step explanation:

Yes.

Assuming a, b and c are integers (not = 0)

a/b + b/c

= (ac + b^2) / bc   which is a rational number.

3 0
2 years ago
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