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3 years ago

Plleeaassee help it is URGENT MAATHH HELP PLEASE WILL GIVE 5 STARS ON ALL CORRECT ANSWERS, MARK AS BEST ANSWER AND SAY THANKS

Mathematics

1 answer:

lara [203]3 years ago

4 0

Using Pythagoras in the first question
c= $\sqrt{16 ^{2} + 4^{2} } =16.4924$
which is approximately 16.5
for the second question
we also use Pythagoras
$b^2=c^2-a^2$
$\sqrt{13^{2}-12^2}=5$

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(11x + 2y) - (5x – y)

omeli [17]

Answer:

the answer is $6x+3y$

Step-by-step explanation:

$\mathrm{Remove\:parentheses}:\\=11x+2y-\left(5x-y\right)\\\\-(5x-y): -5x+y\\=11x+2y-5x+y\\Simplify:\\11x+2y-5x+y: 6x+3y\\\\=6x+3y$

hope this helps :)

Try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations.

5 0

3 years ago

Find a polynomial function of lowest degree with rational coefficients that has the given numbers as some of its zeros. 3-i, squ

SVEN [57.7K]

Real coefients
if a+bi is a root then a-bi is also a root
since 3-i is a root then 3+i s also a root

also the √7, so if √7 is a root then -√7 is also a root
so

f roots are r1 and r2 then the factored form is
f(x)=(x-r1)(x-r2)

roots are 3-i, 3+i and √7 and -√7

f(x)=(x-(3-i))(x-(3+i))(x-√7)(x-(-√7))
expanded
f(x)=x⁴-6x³+3x²+42x-70

8 0

2 years ago

the arlington drama club is selling tickets to an upcoming play. They can sell at most 250 tickets. The adult tickets for $15 ea

allochka39001 [22]

Number of adult tickets = 75

Number of student tickets = 175

Solution:

Let x represents the number of adult tickets and

y represents the number of student tickets.

Total number of tickets sold = 250

⇒ x + y = 250 – – – – (1)

Cost of adult ticket = $15

Cost of student ticket = $5

Total cost of collection = $2000

15x + 5y = 2000 – – – – (2)

Multiply equation (1) by 5

⇒ (1) × 5 5x + 5y = 1250 – – – – (3)

Subtract equation (3) from equation (2), we get

15x + 5y – 5x – 5y = 2000 – 1250

⇒ 10x = 750

⇒ x = 75

Substitute x = 75 in equation (1), we get

⇒ 75 + y = 250

⇒ y = 250 – 75

⇒ y = 175

Number of adult tickets = 75

Number of student tickets = 175

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3 years ago

Six machines, each working at the same constant rate, together can complete a certain job in 12 days. How many additional machin

aev [14]

Answer:

The answer to your question is letter C

Step-by-step explanation:

This is a problem with the inverse rule of three because we expect that more machines can complete the same work in fewer days.

6 machines ------------------ 12 days

x machines ------------------- 8 days

x machines = $\frac{(8 days)(6 machines)}{12 days}$

$x machines = \frac{48 machines}{12}$

x = 4 machines

3 0

2 years ago

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Diano4ka-milaya [45]

Answer:

what grade

Step-by-step explanation:

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2 years ago