3 years ago

Plleeaassee help it is URGENT MAATHH HELP PLEASE WILL GIVE 5 STARS ON ALL CORRECT ANSWERS, MARK AS BEST ANSWER AND SAY THANKS

1 answer:

4 0

Using Pythagoras in the first question
c= $\sqrt{16 ^{2} + 4^{2} } =16.4924$
which is approximately 16.5
for the second question
we also use Pythagoras
$b^2=c^2-a^2$
$\sqrt{13^{2}-12^2}=5$

You might be interested in

PLEASE ANSWER ASAP<br> expand and simplify the following:<br> a) (√6+√3)(√6-√3) b)(√5-√2)(√2+√5)

denis-greek [22]

Answer:

${ \bf{a).}} \\ { \tt{( \sqrt{6} + \sqrt{3} )( \sqrt{6} - \sqrt{3}) }} \\ { \tt{ = ( { \sqrt{6} )}^{2} - {( \sqrt{3}) }^{2} }} \\ { \tt{ = 6 - 3}} \\ { \tt{ = 3}} \\ \\ { \bf{b).}} \\ { \tt{( \sqrt{5} - \sqrt{2})( \sqrt{2} + \sqrt{5} )}} \\ { \tt{ = ( { \sqrt{5} }^{2}) - { (\sqrt{2} }^{2}) }} \\ { \tt{ = 5 - 2}} \\ { \tt{ = 3}}$