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lora16 [44]
3 years ago
14

Four polynomials are shown below:

Mathematics
1 answer:
nikklg [1K]3 years ago
3 0
Both B and D are 3rd degree, but only D is a 3rd degree binomial because it has only 2 terms. The answer is D.
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A student must find the slope of a line that passes through the points (2.2) and (-1, 3). Which of the statements
Evgesh-ka [11]

Answer:

A

Step-by-step explanation:

the formula of the slope is (y2 - y1)/(x2 - x1)

slope = (3-2)/(-1-2) = 1/(-3) = -1/3

6 0
3 years ago
How do I work this problem out
daser333 [38]
What problem I don't see anything
5 0
3 years ago
Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest
natima [27]

Answer:

dependent

Step-by-step explanation:

These two events are dependent.  When the ball is set aside, there are fewer balls  to draw from, so the probability of getting a certain ball becomes greater.

8 0
3 years ago
Read 2 more answers
Help please!!!!!!????!!!!
zavuch27 [327]

Answer:

28 yd²

Step-by-step explanation:

find the two biggest sides

2x4

8 but there are two sides...

8*2= 16

*16*

now side panels

1x4

4 but there are two

4*2= 8

*8*

top and bottom panels

2x1

2 but there are two

2*2= 4

*4*

add them up

16 + 8 + 4= 28  

4 0
3 years ago
Solve for the roots in the equation below. x4 + 3x2 - 4 = 0
fgiga [73]
First, you need to rewrite the expression into binomial form, so you are working with two terms (as you world with a quadratic):
(x²)²-3(x²)-4=0
Now, you can place the x²s into brackets as the coefficient is now 1:
(x²  )(x²  )
Next, find out two numbers that add together to give you -3 and multiply to give -4 (these are the leftover integers after removing the x²s). These two numbers are -4 and 1.
Place the -4 and 1 into the brackets:
(x²-4)(x²+1)=0
Notice that the x²-4 is a difference of two squares, so can be further factorised into (x+2)(x-2)
This leaves you with a final factorisation of:
(x+2)(x-2)(x²+1)=0
Now we handle each bracket individually to obtain our four solutions for x:
x+2=0
x=-2
x-2=0
x=2
x²+1=0
x²=1
x=<span>±1</span>

8 0
3 years ago
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