At the beining, he has 76
that is at x=0
y=mx+76
find m
given
when x=2, y=100
find m
100=2m+76
minus 76 both sides
24=2m
divide both sides by 2
12=m
the equatin is
y=12x+76
1. 7+ (-9) = 7-9=-2
2.(-8) + (+5)= -8+5= -(8-5)=-3
3.(+9) - (-3) = 9+3=12
4.(+12) - (-1) = 12+1=13
5. (-7) - (-5) = -7+5==(7-5)=-2
<span>(-14) - (+2) = -14-2=-(14+2)=-16</span>
Answer:
we can make 5 servings of spice rub from 10 table spoons of onion powder
Step-by-step explanation:
Given the data in the question;
2 table spoon of onion powder makes one serving of spice rub.
Total table spoons of onion powder available = 10
So Let x represent the number of servings of spice rub we can make from our 10 table spoons of onion powder ;
2 table spoons = 1 servings
10 table spoons = x servings
we cross multiply;
x servings × 2 table spoons = 10 table spoons × 1 servings
x servings = ( 10 table spoons × 1 servings ) / 2 table spoons
x = 10 / 2
x = 5 servings
Therefore, we can make 5 servings of spice rub from 10 table spoons of onion powder
Let x represent the larger number.
Let y represent the smaller number.
x-y=4 Given
3x=5y-2 Given
Now we can just substitute; let x=4+y
Substitute 4+y for x in the second equation:
3(4+y)=5y-2
12+3y=5y-2
-2y=-14
y=7
Substitute back (into BOTH equations to double check work).
x, the larger number, is 11
Answer:
<h2>Multiplication.</h2>
Step-by-step explanation:
The given expression is
![5+(9x-3) \div 2](https://tex.z-dn.net/?f=5%2B%289x-3%29%20%5Cdiv%202)
For
, we have
![5+(9(5)-3) \div 2](https://tex.z-dn.net/?f=5%2B%289%285%29-3%29%20%5Cdiv%202)
Notice that the first operation we need to do is multiplication, because that's the right order of operations when we solve these kind of expressions.
![5+(45-3) \div 2](https://tex.z-dn.net/?f=5%2B%2845-3%29%20%5Cdiv%202)
Then, we subtract
![5+42 \div 2](https://tex.z-dn.net/?f=5%2B42%20%5Cdiv%202)
Now, we divide
![5+21](https://tex.z-dn.net/?f=5%2B21)
Finally, we sum
![26](https://tex.z-dn.net/?f=26)
Therefore, the right answer is multiplication.