Product is the answer to a multiplication problem so we multiply g and 4.
4xg or 4(g). Or even simpler, you could do 4g.
hope it helps!
If there are two songs written and the longest one is 126 seconds less than twice the length of the short song, and the longest one lasts 286 seconds, then the shorter song's length can be found using this formula:
2x-126=286.
This would then turn into x-63=143 to show the time difference. Solving here for x, would be 206 seconds.
Answer:
Step-by-step explanation:
Given that the height in inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84.
X is N(64, 2.8)
Or Z = 
a) the probability that the height of a randomly chosen woman is between 59.8 and 68.2 inches.

b) 
c) For 4 women to be height 260 inches is equivalent to
4x will be normal with mean (64*4) and std dev (2.8*4)
4x is N(266, 11.2)

d) Z is N(0,1)
E(Z19) = 
since normal distribution is maximum only between 3 std deviations form the mean on either side.
I order to solve this you have to find out how how much root beer there is to the total amount of candy. 12/27. Then you find out what the percentage of root beer there is by dividing 12 by 27. It’ll give you a decimal point. Percentage has a maximum of 100%. And you’ll find out what percent based on this decimal. Factor it out of 1. The percentage you get is .44. By factoring out of 1 you can find out that the percentage is 44%. So the probability of finding a root beer out of all the candy is roughly 44%
Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS =
= 57.5°
Now, tan(57.5°) = 
⇒ 1.5697 = 
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) = 
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = (
) × (ST)
= (
) × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²