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Usimov [2.4K]
3 years ago
8

the professor is decorating his home and wants to buy some plants. he is interested in three types of plants costing $7, $10, an

d $13. his budget is $150 and wants to buy 15 plants. translate the information into a system of two linear equations in three variables. find all solutions of the system. specify at least three of his options.
Mathematics
1 answer:
Luda [366]3 years ago
3 0
X quantity of first plant which cost $7
y quantity of second plant which cost $10
z quantity of third plant which cost $13

{x+y+z=15
{7x+10y+13z=150
There are 8 solutions with spending $150
Five of them are:
1x$7 +  13x$10 + 1x$13
2x$7  + 11x$10  +2x$13
3x$7 +  9x$10  +3x$13
5x$7  +  5x$10 + 5x$13
6x$7 + 3x$10 + 6x$13
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3 years ago
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ivolga24 [154]

Answer:

b = 10

Step-by-step explanation:

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Multiply both sides by 2 to clear the fraction

b(3x + 15) = 30x + 150

Divide both sides by (3x + 15)

b = \frac{30x+150}{3x+15} ← factor numerator and denominator

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7 0
3 years ago
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feasible region is shaded in the attached graph

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2.4     9

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