Answer:
a) $14,600.
Explanation:
The computation of the company total assets are shown below:
= Cash balance + supplies balance + equipment balance
where,
Cash balance = investment amount + borrowed amount - paid amount for equipment
= $6,200 + $3,200 - $2,120
= $7,280
And, the other item values would remain the same
Now put these values to the above formula
So, the value would equal to
= $7,280 + $1,120 + $6,200
= $14,600
Answer:
True.
Explanation:
To write a professional letter, some standard format rules need to be followed.
It is necessary that the letter is written using a formal vocabulary, with clear and precise information, in the appropriate format, containing date, information about your professional profile, about the company and a final greeting.
To achieve an important objective, such as getting a job, it is important to have good writing skills to write a professional letter, in order to demonstrate through your arguments, your skills and competences, which can contribute to the success of a company.
Money is a kind of asset in an economy that is castoff to purchase goods and amenities from other people. A commodity is a physical thing that is willingly substitutable with one more item of the same type. Commodity money is a commodity that has intrinsic value. Intrinsic value is the commodity has worth though it is not used as money. So the answer is a woman offers her neighbor a US silver dollar in exchange for a bicycle.
Answer:
interest rate r = 6.78 %
Explanation:
given data
investment = $12,000
interest rate = 3.5 percent = 0.035
time = 5 year
interest rate = 7.9 percent = 0.079
time = next 15 year
to find out
What was your annual rate of return over the entire 20 years
solution
we get here interest rate as
interest rate r = ![[(1+r)^{t1} * (1+r)^{t2}]^{\frac{1}{t1+t2}} - 1](https://tex.z-dn.net/?f=%5B%281%2Br%29%5E%7Bt1%7D%20%2A%20%281%2Br%29%5E%7Bt2%7D%5D%5E%7B%5Cfrac%7B1%7D%7Bt1%2Bt2%7D%7D%20-%201)
...................1
here t1 is time period for first 5 year and t2 is time i.e next 15 year and r1 and r2 is rate
now put here value we get
interest rate r = ![[(1+)^{t1} * (1+r)^{t2}]^{\frac{1}{t1+t2}} - 1](https://tex.z-dn.net/?f=%5B%281%2B%29%5E%7Bt1%7D%20%2A%20%281%2Br%29%5E%7Bt2%7D%5D%5E%7B%5Cfrac%7B1%7D%7Bt1%2Bt2%7D%7D%20-%201)
interest rate r = ![[(1+0.035)^{5} * (1+0.079)^{15}]^{\frac{1}{5+15}} - 1](https://tex.z-dn.net/?f=%5B%281%2B0.035%29%5E%7B5%7D%20%2A%20%281%2B0.079%29%5E%7B15%7D%5D%5E%7B%5Cfrac%7B1%7D%7B5%2B15%7D%7D%20-%201)
interest rate r = 1.0678 - 1
interest rate r = 0.0678
interest rate r = 6.78 %
