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jeka94
4 years ago
5

Give two reasons why we feel earths gravity more strongly than the moons gravity

Physics
2 answers:
DaniilM [7]4 years ago
8 0

1).  The Earth has about 80 times as much mass as the Moon has.

2). The Earth is closer to many of us than the Moon is.

adell [148]4 years ago
8 0

Answer:

Explanation:

The force of gravity is the physical force exerted by the mass of a planet on the objects that are within its gravitational field. In other words, this law establishes that bodies, by simply having mass, experience a force of attraction to other bodies with mass.

The force of gravity depends on the mass of each object. The force with which two objects are attracted is proportional to their mass and decreases rapidly with distance:

<em>F=G*\frac{m1*m2}{r^{2} }</em>

where G is the universal gravitation constant, whose value is

G=6.673*10⁻¹¹ \frac{N*m^{2} }{kg^{2} }

This expression indicates that the gravitational force that a point mass M exerts on another point mass m that is at a distance r from the previous one is directly proportional to the product of the masses and inversely proportional to the square of the distances that separates them.

Given the above, it is possible to say that two reasons why we feel the Earth's gravity more strongly than the moon's gravity are:

  • Being the mass of a person the same, the mass of the Earth is greater than the mass of the Moon
  • The distance r between the Earth and us is much closer than the distance r between the Moon and us (remember that the Earth exerts its force of gravity from the center)

This causes the force exerted by the Earth on us to be much greater.

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An electron, tial well may be anywhere within the interval 2a. So the uncertainty in its position is Δx= 2a. There must be a co
lapo4ka [179]

Answer:

      K =  \frac{h'}{8 m  \ \Delta x^2}K

Explanation:

The Heisenberg uncertainty principle is

          Δx Δp ≥ h' / 2

          h’ =\frac{h}{2\pi }

The kinetic energy of a particle is

          K = ½ m v²

           p = mv

           v = \frac{p}{m}

substitute

           K = \frac{1}{2}  \frac{p^2}{m}

from the uncertainty principle,

           Δp = \frac{h'}{2 \ \Delta x}

we substitute

          K = \frac{1}{2m} ( \frac{h'}{2 \ \Delta x})^2

          K =  \frac{h'}{8 m  \ \Delta x^2}

4 0
3 years ago
Which statement best describes the movement of atoms in a solid?
Helga [31]

Answer:

They have no freedom to move

Explanation:

Particles can be solids, liquids and gases.

Solids are the substances in which the atoms are very close to each other. It is very difficult to separate the molecules. The atoms cannot move from one place to another.  The inter molecular forces between them is very strong.

Hence, the correct option that describes the movement of atoms in a solid is (c) "They have no freedom to move".

5 0
4 years ago
Compare and contarst the difference between saturated and unsaturated solutions and supersaturated
JulsSmile [24]

Answer:

Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible

6 0
2 years ago
A wire with a circular cross section and a resistance R is lengthened to 9.66 times its original length by pulling it through a
damaskus [11]

Answer:

The resistance of the wire after it is stretched is 93.31R.

Explanation:

Resistance is the property of the material to oppose the current flow through it. It is given by the relation :

R = (ρl)/A

Here ρ is resistivity, l is length of wire and A is the area of the wire.

Let l₀, and A₀ are the original length and original circular cross section area of the wire. while l₁ and A₁ are the new length and new circular cross section area of the wire.

Volume of the original wire, V₀ = A₀ x l₀

Volume of the new wire, V₁ = A₁ x l₁

According to the problem. volume remain same. So,

V₀ = V₁

A₀ x l₀ = A₁ x l₁

It is given that l₁ = 9.66 x l₀. Substitute this value in the above equation;

A₀ x l₀ = A₁ x 9.66 x l₀

A₁ = A₀/9.66

Resistance of the original wire, R = (ρl₀)/A₀

Resistance of the new wire, R₁ = (ρl₁)/A₁

Substitute the value of l₁ and A₁ in the above equation.

R₁ = (ρ x l₀ x 9.66)/(A₀/9.66) = 93.31 x (ρl₀)/A₀

But (ρl₀)/A₀ = R. hence,

R₁ = 93.31 R

8 0
3 years ago
A car travels along a straight road, heading east for 1 h, then traveling for 30 min on another road that leads northeast. If th
Bogdan [553]

Answer:

The car is 72.75 miles away from its starting position.

Explanation:

First, remember the relation:

distance = time*speed.

Also, the distance between two points (a, b) and (c, d) is:

D = √( (a - c)^2 + (b - d)^2)

For this problem, we can assume:

The North is equivalent to the y-axis, and the East is equivalent to the x-axis.

We also assume that the initial position of the car is (0mi, 0mi)

Now the car moves to the East at a speed of 52mi/h for one hour, then the new position of the car is:

(0mi, 0mi) + (52mi/h*1h, 0mi) = (52mi, 0mi)

Now the car travels 30 mins (or 0.5 hours) to the northeast at a speed of 52mi/h.

We can assume that it moves at an exact angle of 45° from East to North, then the components of the speed can be written as:

Sx = speed in the x-axis = 52mi/h*cos(45°) = 36.77 mi/h

Sy = speed in the y-axis = 52mi/h*sin(45°) =  36.77 mi/h

Then the new position of the car is:

(52mi, 0mi) + (36.77 mi/h*0.5h, 36.77 mi/h*0.5h) = (70.385 mi, 18.385 mi)

Now we know the final position of the car.

The distance between the final position (70.385 mi, 18.385 mi) and the initial position (0mi, 0mi) is:

D = √( (70.385 mi - 0mi)^2 + (18.385 mi - 0mi)^2) = 72.75 mi

The car is 72.75 miles away from its starting position.

7 0
3 years ago
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